Answer:
2.35 kgm^2
Explanation:
we take length 68.7 cm as x-axis and 47.5 cm as y-axis then the axis about which we have to find out moment of inertia will be z-axis.
moment of inertia about x-axis
kg-m2
by perpendicular axis theorem
Answer:
e. Only(a) and (b) above are correct
Explanation:
Impulse
= Fx t = m ( v-u )
v-u = change in velocity
F x t = mass x change in velocity
change in velocity = F t / mass
=a t
change in velocity ∝ t ( time ) , if a is constant
dv = a_avg dt
∫dv = a_avg ∫dt
v-u = a_avg t
change in velocity ∝ t ( time )
So both (a) and (b) are correct.
Answer:
a) 8.61 m/s, b) 5.73 m
Explanation:
a) During the collision, momentum is conserved.
mv = (m + M) V
(12.5 g) (86.4 m/s) = (12.5 g + 113 g) V
V = 8.61 m/s
b) After the collision, energy is conserved.
Kinetic energy = Work done by friction
1/2 (m + M) V² = F d
1/2 (m + M) V² = N μk d
1/2 (m + M) V² = (m + M) g μk d
1/2 V² = g μk d
d = V² / (2g μk)
d = (8.61 m/s)² / (2 × 9.8 m/s² × 0.659)
d = 5.73 m
Notice we used the kinetic coefficient of friction. That's the friction when an object is moving. The static coefficient of friction is the friction on a stationary object. Since the bullet/block combination is sliding across the surface, we use the kinetic coefficient.
Explanation:
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