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Vlada [557]
3 years ago
5

Before colliding the momentum of block A is +15.0 kg*m/s, and block B is -35.0 kg*m/s. after, block A has a momentum -12.0 kg*m/

s. what is the momentum of block B afterwards. PLEASE HELP ME!!!!!!!!! IM MARKING BRAINLIEST
Physics
1 answer:
UkoKoshka [18]3 years ago
3 0

The momentum of block B afterwards is -8.0 kg m/s.

Explanation:

We can solve this problem by applying the principle of conservation of momentum.

In fact, the total momentum before and after the collision must be conserved. Therefore, we can write:

p_A + p_B = p_A' + p_B'

where:

p_A = +15.0 kg m/s is the initial momentum of block A

p_B = -35.0 kg m/s is the initial momentum of block B

p_A' = -12.0 kg m/s is the final momentum of block A

p_B' is the final momentum of block B

Solving for p_B', we find:

p_B' = p_A + p_B - p_A' = +15.0 +(-35.0) - (-12.0)=-8.0 kg m/s

So, the momentum of block B afterwards is -8.0 kg m/s.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

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