Before colliding the momentum of block A is +15.0 kgm/s, and block B is -35.0 kgm/s. after, block A has a momentum -12.0 kg*m/

Question

3 years ago

5

s. what is the momentum of block B afterwards. PLEASE HELP ME!!!!!!!!! IM MARKING BRAINLIEST

1 answer:

UkoKoshka [18] · Answer 1 · 2022-02-25T22:33:30+03:00

The momentum of block B afterwards is $-8.0 kg m/s$ .

Explanation:

We can solve this problem by applying the principle of conservation of momentum.

In fact, the total momentum before and after the collision must be conserved. Therefore, we can write:

$p_A + p_B = p_A' + p_B'$

where:

$p_A = +15.0 kg m/s$ is the initial momentum of block A

$p_B = -35.0 kg m/s$ is the initial momentum of block B

$p_A' = -12.0 kg m/s$ is the final momentum of block A

$p_B'$ is the final momentum of block B

Solving for $p_B'$ , we find:

$p_B' = p_A + p_B - p_A' = +15.0 +(-35.0) - (-12.0)=-8.0 kg m/s$

So, the momentum of block B afterwards is $-8.0 kg m/s$ .

Learn more about momentum:

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Before colliding the momentum of block A is +15.0 kg*m/s, and block B is -35.0 kg*m/s. after, block A has a momentum -12.0 kg*m/