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Nitella [24]
2 years ago
13

I WILL MARK YOU THE BRAINLIEST NO LINKS AND IF YOU DONT UNDERSTAND THE QUESTION DONT ANSWER

Physics
1 answer:
elena-s [515]2 years ago
6 0

Answer:

Perform a simple test of the material in the pan to assess whether it is real gold. Raw gold appears brassy yellow and bright. If you think it is gold, place your hand between it and the sun to create shade over the gold. If it still appears bright in the pan, chances are that it is real gold.

Explanation:

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A kickoff sends a football with an initial velocity of 25 m/s at an angle of 50
eduard

Answer:

The x-component of the velocity is 16.07 m/s

The y-component of the velocity is 19.15 m/s

Explanation:

Given;

initial velocity of the football, u = 25 m/s

angle of projection, θ = 50⁰

The x-component of the velocity (horizontal component) is given as;

V_x = Vcos(50^0)\\\\V_x = 25 \ m/s \ \ \times \ \ 0.6428\\\\V_x = 16.07 \ m/s

The y-component of the velocity (vertical component) is given as;

V_y = Vsin(50^0)\\\\V_y = 25 \ m/s \ \ \times \ \ 0.766\\\\V_y = 19.15 \ m/s

7 0
2 years ago
calculate the energy spent on spraying a drop of mercury of 1 cm radius into 10^6 droplets all of same radius. surface tension o
WARRIOR [948]

Answer:

ANS : .Energy spent on spraying =4.3542*10^{-4}J

Explanation:

<em>Given:</em>

  • <em>Radius of mercury = 1cm initially ;</em>
  • <em>split into 10^{6} drops ;</em>

Thus, volume is conserved.

i.e ,

\frac{4}{3} \pi R_{o}^{3} = 10^{6}*\frac{4}{3} \pi R_{n}^{3}\\R_{n}=\frac{R_{o}}{10^{2}} = \frac{1cm}{100} = 0.01 cm

  • Energy of a droplet = TΔA

Where ,

  • <em>T is the surface tension </em>
  • <em>ΔA is the change in area</em>

Initial energy E_{i} = T*A_{i}\\= 0.0035 * 4 *\pi *0.01^{2}\\=4.398*10^{-6}J

Final energy E_{f}=10^{6}*T*A_{f}\\=10^{6}*0.0035*4*\pi *(0.0001)^2\\=4.39823*10^{-4}

∴  .Energy spent on spraying = =E_{f}-E{i}\\=(439.823-4.39823)*10^{-6}\\=4.3542*10^{-4}J

ANS : .Energy spent on spraying =4.3542*10^{-4}J

6 0
2 years ago
Which two statements explain how water weathers and erodes rock?
Zinaida [17]
It’s E cause water when it freezes it expands and water flows down
8 0
3 years ago
Read 2 more answers
Write a message about an important aspect of life on earth to be sent beyond our solar system
zepelin [54]
We grow crops (plants) on earth, so it's very important for that to go beyond earth because if there is no way to grow crops, we won't get enough nutrients from some synthetic (fake) food. hope I helped! :)
6 0
3 years ago
When a 20-V emf is placed across two resistors in series, a current of 2.0 A is present in each of the resistors. When the same
ehidna [41]

Answer:

7.24 ohm

Explanation:

Let R1 and R2 are resistance of two resistors.

Emf=E=20 V

Current,I=2 A

Current,I'=10 A

We have to find the magnitude of the greater of the two resistances.

In series

R=R_1+R_2

V=IR

By using the formula

20=2(R_1+R_2)

R_1+R_2=\frac{20}{2}=10...(1)

In parallel

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}

\frac{1}{R}=\frac{R_2+R_1}{R_1R_2}

R=\frac{R_1R_2}{R_1+R_2}

20=10(\frac{R_1R_2}{R_1+R_2}

2=\frac{R_1R_2}{10}

R_1R_2=20

R_2=\frac{20}{R_1}

Substitute the value

\frac{20}{R_1}+R_1=10

R^2_1+20=10R_1

R^2_1-10R_1+20=0

R_1=\frac{10\pm\sqrt{(-10)^2-4(20)}}{2}

By using quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

R_1=\frac{10\pm 2\sqrt 5}{2}

R_1=\frac{10+2\sqrt 5}{2}=5+\sqrt 5=7.24 ohm

R_1=\frac{10-2\sqrt 5}{2}=2.76 ohm

Substitute the value

R_2=\frac{20}{7.24}=2.76 ohm

R_2=\frac{20}{2.76}=7.24 ohm

Hence, the magnitude of the greater of the two resistance=7.24 ohm

8 0
3 years ago
Read 2 more answers
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