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yKpoI14uk [10]
3 years ago
13

How do liquids affect friction?

Physics
1 answer:
Sophie [7]3 years ago
6 0

Although liquids offer resistance to objects moving through them, they also smooth surfaces and reduce friction. Liquids tend to get thinner (less viscous) as they are heated. ... The rubbing produces friction and the result is heat.
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A skier is traveling fast down a mountain slope. The table shows data
melisa1 [442]

Answer:

The pushing force and the skier's mass

(A) is correct option.

Explanation:

Given that,

Mass = 64 kg

Weight = 608 N

Velocity = 21 m/s

Forward force = 45 N

We need to calculate the reaction force of the snow pushing  on the skier

Using given data,

The reaction force of the snow pushing  on the skier is equal to the pushing force and the skier's mass.

Hence, The pushing force and the skier's mass

(A) is correct option.

6 0
3 years ago
Does the work cause a change in kinetic energy or a potential energy?
Alla [95]

Answer:

Work cause a change in kinetic energy

3 0
3 years ago
The bottom is hard what is the answers
riadik2000 [5.3K]
11. aboard
12. marsh
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please vote my answer brainliest! thanks.
7 0
3 years ago
A 35.9 g mass is attached to a horizontal spring with a spring constant of 18.4 N/m and released from rest with an amplitude of
lidiya [134]

Answer:

7.74m/s

Explanation:

Mass = 35.9g = 0.0359kg

A = 39.5cm = 0.395m

K = 18.4N/m

At equilibrium position, there's total conservation of energy.

Total energy = kinetic energy + potential energy

Total Energy = K.E + P.E

½KA² = ½mv² + ½kx²

½KA² = ½(mv² + kx²)

KA² = mv² + kx²

Collect like terms

KA² - Kx² = mv²

K(A² - x²) = mv²

V² = k/m (A² - x²)

V = √(K/m (A² - x²) )

note x = ½A

V = √(k/m (A² - (½A)²)

V = √(k/m (A² - A²/4))

Resolve the fraction between A.

V = √(¾. K/m. A² )

V = √(¾ * (18.4/0.0359)*(0.395)²)

V = √(0.75 * 512.53 * 0.156)

V = √(59.966)

V = 7.74m/s

8 0
3 years ago
Read 2 more answers
Two metal plates 15mm apart have a potential difference of 750v between them. The force on a small charged sphere placed between
Romashka [77]

Answer:

50,000 V/m

Explanation:

The electric field between two charged metal plates is uniform.

The relationship between potential difference and electric field strength for a uniform field is given by the equation

\Delta V=Ed

where

\Delta V is the potential difference

E is the magnitude of the electric field

d is the  distance between the plates

In this problem, we have:

\Delta V=750 V is the potential difference between the plates

d = 15 mm = 0.015 m is the distance between the plates

Therefore, rearranging the equation we find the strength of the electric field:

E=\frac{\Delta V}{d}=\frac{750}{0.015}=50,000 V/m

6 0
4 years ago
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