Answer:
lowest frequency = 535.93 Hz
distance between adjacent anti nodes is 4.25 cm
Explanation:
given data
length L = 32 cm = 0.32 m
to find out
frequency and distance between adjacent anti nodes
solution
we consider here speed of sound through air at room temperature 20 degree is approximately v = 343 m/s
so
lowest frequency will be =
..............1
put here value in equation 1
lowest frequency will be =
lowest frequency = 535.93 Hz
and
we have given highest frequency f = 4000Hz
so
wavelength =
..............2
put here value
wavelength =
wavelength = 0.08575 m
so distance =
..............3
distance =
distance = 0.0425 m
so distance between adjacent anti nodes is 4.25 cm
<span>earth would be thrown off its balance and nature would be in danger of too many resources and not enough resources </span>
1. One
2. Oohm
Hope this helps
Answer:
30.5 x 10³ min.
Explanation:
Atomic weight of aluminium = 27
For the reaction
Al⁺³ + 3e = Al
3 mole of electron is required by 1 mole of aluminium
3 x 96500 C of charge is required for 27 gram of aluminium
60.2 g aluminium will require

645.47 x 10³ C
So charge required = 645.47 x 10³ C
Now Charge = Current x time
Current ( given ) = 0.352A
Time = charge / current = 645.47 x 10³ / .352
=1833 x 10³ s
30.5 x 10³ minutes