A 1.30-m long gas column that is open at one end and closed at the other end has a fundamental resonant frequency 80.0 Hz. What
1 answer:
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Answer:
where L is the length of the ramp
Explanation:
Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.
The parallel component would have a magnitude of
We can use the following equation of motion to find out the final velocity of the book after sliding L m:
where v m/s is the final velocity, = 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and
is the distance traveled:
Answer:
Current, I = 0.153 A
Explanation:
Given that,
Radius of the circular conducting loop, r = 0.5 m
Resistance of the resistor,
Magnetic field, B = 1 T
Angle with z axis,
Magnetic field increases to 10 T in 4 seconds
To find,
Magnitude of current.
Solve,
According to Faraday's law, the induced emf is given by:
are final flux and the initial flux respectively.
The magnitude of current can be calculated using the Ohm's law as :
I = 0.153 A
Therefore, the magnitude of the current that will be caused to flow in the loop is 0.153 A.
Answer:
the diameter of the outside edge of the receiver is
Explanation:
From the schematic free body diagram illustrating what the question is all about below;
Let represent A to be the vertex where the receiver is being placed
S to be the focus
BP to be equal to r (i.e radius of the outer edge)
BC to be 2 r (i.e the diameter)
Given that AS = 4 in and AP is 18 in
Let AP be x- axis and AY be y -axis
A=(0,0)
S=(4,0) = (0,0)
So that the equation of the parabolic path of the receiver will be:
B = (AP, BP)
B = (18, r)
B lies y² = 16 x
r² = 16 x
r² 16 × 18
Diameter BC = 2r
