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Airida [17]
3 years ago
9

An electromagnetic radio wave is received by a transmitter before it is converted to a sound wave. The radio wave has a waveleng

th of 23,076 m and a frequency of 13,000 Hz. What velocity is the wave traveling at before the transmitter converts it to a sound wave? 1. 76 m/s 0. 56 m/s 3. 31 × 102 m/s 3. 00 × 108 m/s.
Physics
1 answer:
snow_tiger [21]3 years ago
8 0

The velocity the wave was traveling at before the transmitter converts it to a sound wave is 3.0 x 10⁸ m/s.

<h3>What is Velocity of waves?</h3>

The velocity of waves is the rate of change of the wave's displacement with time.

The velocity of waves is determined by taking the product of the wave's frequency and wavelength.

v = fλ

v = 13,000 x 23,076

v = 3.0 x 10⁸ m/s.

Thus, the velocity the wave was traveling at before the transmitter converts it to a sound wave is 3.0 x 10⁸ m/s.

Learn more about velocity of waves here:  brainly.com/question/13867834

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The rod of the fixed hydraulic cylinder is moving to the left with a constant speed vA = 25 mm/s. Determine the corresponding ve
Montano1993 [528]

Explanation:

let vertical distance from A to C be  h=250mm the constraint equation is:

l_{ac} +l_{ab} =L

we want to find l_{bc} distance can be written as l_{bc} =h_{1}+h_{2} which we will find by using Pythagorean theorem h 1 is a constant and can be written as h:

h_{2} =\sqrt{l_{ab}^2- s_{A} ^2}

l_{ac} =\sqrt{s_{A}^2+ h^2 }

l_{ab} =L-\sqrt{s_{A} ^2+h^2 }

taking derivative w.r.t time we get

h^._{2} =-v_{B =(l_{ab} l_{ab} ^.-s_{A} v_{A} )/h_{2}

l_{ab} ^.=(s_{A} v_{A} )/l_{ab} -L

given s_{A} =425mm which gives us

l_{ab} =1050-\sqrt{450^2+250^2} =556.923mm\\\\h_{2} =\sqrt{556.923^2-425^2}=359.914mm

l_{ab} ^.=(425.25)/(556.923-1050)=-21.548mm\\\\-v_{B} =(-556.923*21.548-425.25)/(359.914)\\\\v_{B} =62.864mm/s

5 0
4 years ago
The impulse given to a ball with mass of 2 kg is 16 N*s. If the ball starts from rest, what is its final velocity?
Alik [6]
The impulse is equal to the variation of momentum of the object:
I=\Delta p = m \Delta v
where m is the mass object and \Delta v = v_f - v_i is the variation of velocity of the object.

The ball starts from rest so its initial velocity is zero: v_i=0. So we can rewrite the formula as
I=m v_f
or 
v_f =  \frac{I}{m}

and since we know the impulse given to the ball (I=16 Ns) and its mass (m=2 kg), we can find the final velocity of the ball:
v_f =  \frac{16 Ns}{2 kg}=  8 m/s
7 0
3 years ago
Read 2 more answers
How do you answer number 3 a and b?
netineya [11]
I would assume you answer them by doing the math required.
7 0
4 years ago
Two sources of error and precaution in the centre of gravity experiment​
Karo-lina-s [1.5K]

Answer:

The answer to this question is given below in this explanation sections.

Explanation:

The weight of an object is concentrated at the center of gravity.The term center of gravity is used interchangeably with center of mass.For a symmetrical object the center of mass is located  at the geometric  center of the object.If the object is not symmetric we can determined the center of mass using the mentioned below.

Materials:

  • cardboard
  • weight(washer,bolt,or fishing weight)
  • hole punch
  • pencil

Procedure:

  1. Cut the cardboard into a strange shape.Do not use a circle,square,rectangle,or any other common geometric shape.
  2. Punch a hole near the edge of the cut-out cardboard piece and hang it from a nail.
  3. Place the weight, a washer or bolt, on a thread and tie it off.
  4. Hang the thread and weight from the nail in front of the cardboard.
  5. use a pencil to draw a plumb line down the cardboard where the thread touches.This mark your center  line from that hanging point.

conclusion:

             What would happen to the center of gravity of the shape if you were to spin it freely?

center of gravity experiment:

  1. Balance a ruler with a hammer.Take a rubber band or string and make a loose loop around the hammer and ruler. Make sure the end of the hammer is touching the ruler,and then positions the ruler at the edge of the table.
  2. Balance two forces with  a toothpick.A common magic  trick using the properties of center of gravity.The two forks are balanced on the edge of the glass by a toothpick.
  3. Stand with your back and feet against a wall.Have someone place quarter on the floor at your feet.Try to pick it cup.Most people cant make these adjustments.
  4. Stand against a wall sideways with your arm and leg touching the wall,with nothing to from the out away hold onto.Try to lift your other leg straight out away from the wall.you wont be able to do it.
  5. The girls away win chairs lifting challanges place dining chairs against a wall.Bend over the chair so that your head touches the wall and you upper body is parallel to the floor.lift the chair to your chest to your chest and then try to stand up.
7 0
3 years ago
A power plant produces 1000 MW to suply a city 40Km away.Current flows from the power plant on a single wire of resistance0.050
Westkost [7]

Answer:

The current in wire resistance 2Ω

a). 8696 A

b). fraction power 15.1% a 115kV

Explanation:

Resistance

R=0.05Ω/Km*40km

R=2Ω

P=1000 MW

a).

P=V*I\\I=\frac{P}{V}=\frac{1000x10^{6}W}{115x10^{3}k }  =8696.65A

Using law ohm

b).

V=I*R\\I=\frac{V}{R}

P=I*I*R\\P=I^{2} *R\\P=8696.65^{2}*2\\P=151.228 x10^{6}  W

e=\frac{151.228x10^{6} }{1000x10^{6} }*100= 15.12%

8 0
4 years ago
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