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forsale [732]
3 years ago
3

To what decimal place should each answer be rounded? How many significant figures does the rounded answer have? 101 cm − 99.1 cm

= 1.9 cm (unrounded) After rounding, the answer should be reported to the tenths place and thus has significant figures . 0.5 atm + 9.8 atm = 10.3 atm (unrounded) After rounding, the answer should be reported to the tenths place and thus has 2 siginificant figures .
Chemistry
1 answer:
BabaBlast [244]3 years ago
7 0

Answer :

The answer will be, 2 cm and the number of significant figures is, 1

The answer will be, 10.3 cm and the number of significant figures are, 3

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

(1) As we are given:

101cm-99.1cm=1.9cm

In the given expression, 101 has 3 significant figures and 99.1 has 3 significant figures. From this we conclude that least precise number present after the decimal point is 0 that means there is no number after decimal.

Thus, the answer will be, 2 cm and the number of significant figures is, 1

(2) As we are given:

0.5atm+9.8atm=10.3atm

In the given expression, 0.5 has 1 significant figures and 9.8 has 2 significant figures. From this we conclude that least precise number present after the decimal point is 1.

Thus, the answer will be, 10.3 cm and the number of significant figures are, 3

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Answer:

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Other methods are:

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(Volume of the component/Total volume of the solution) x 100

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i.e. Mass by Volume percentage =

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Here's a point to be kept in mind :

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The concentration of a solution is most of the time expressed as the number of moles of solute present in 1 Liter of the solution (also called molarity )

(There are also other ways to express concentration. Please follow this link. )

EXAMPLE:

(a) If 25 moles of NaCl are present in 100 L of a solution wherein H2O is the solvent, then the concentration of the solution is

25

100

=

0.25

mol⋅L

−

1

.

(b) What is the molarity of a solution prepared by dissolving 15.0 g of sodium hydroxide in enough water to make a total of 225 mL of solution?

Solution

Calculate the number of moles of solute present.

Moles of NaOH = 15.0 g NaOH ×

1

mol NaOH

40.00

g NaOH

= 0.375 mol NaOH

Calculate the number of litres of solution present.

Volume = 225 mL ×

1

L

1000

mL

= 0.225 L soln

Divide the number of moles of solute by the number of litres of solution.

Molarity =

0.375

mol

0.225

L

= 1.67 mol/L

Explanation:

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