<span>To determine the pH of the solution given, we make
use of the acid equilibrium constant (Ka) given. It is the ratio of the
equilibrium concentrations of the dissociated ions and the acid. The
dissociation reaction of the CH3COOH acid would be as follows:
</span>CH3COOH = CH3COO- + H+<span>
The acid equilibrum constant would be expressed as follows:
Ka = [H+][</span>CH3COO-] / [CH3COOH] = 1.8× 10^–5
<span>
To determine the equilibrium concentrations we use the ICE table,
CH3COOH H+ </span>CH3COO<span>-
I 1.60 0 0
C -x +x +x
----------------------------------------------------------------
E 1.60-x x x
</span>1.8× 10^–5 = [H+][CH3COO-] / [CH3COOH] <span>
1.8 x 10^-5 = [x][x] / [0.160-x] </span>
Solving for x,
x = 1.69x10^-3 = [H+] = [F-]
pH = -log [H+] = -log [1.69x10^-3] = 2.8
CO₂ has 4 + 2(6) = 16 valence electrons
CO₂ have linear molecular structures with a 180° bond angle. CO₂ is nonpolar because the individual bond dipoles cancel each other out
XeCl₂ has 8 + 2(7) = 22 valence electrons.
There are five pairs of electrons about the central Xe atom. The structure will be based on a trigonal bipyramid geometry. The most stable arrangement of the atoms in XeCl₂ is a linear molecular structure with a 180° bond angle. It is nonpolar because the Xe−Cl bond dipoles and lone pairs around Xe are arranged in such a manner that they cancel each other out.
(b)
SCl₆ is nonpolar because it has 6 bonding pairs and no lone pairs, giving it an octahedral shape. When you draw the vectors, you can see that the resultant is 0, making it nonpolar.
SCl₄ on the other hand is polar because it has 4 bonding pairs and one lone pair, giving it a trigonal pyramidal shape.
SCl₂ is also polar due to reasons similar to those in the case of SCl₄.
Trisulfer-dodecacarbonide
(maybe)
Answer:
Usually you have V, for voltage, Ohms for resistance, and Coulombs for charge.
Explanation:
See the image attached :)
A … correct me if I’m wrong sorry it just makes sense from the picture
