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GuDViN [60]
4 years ago
11

Wildflowers bloom in early spring so they are not shaded by trees, which grow their leaves back later in spring. This is an exam

ple of competition for _____.
Chemistry
2 answers:
katrin2010 [14]4 years ago
5 0
Sunlight or just light. 
gtnhenbr [62]4 years ago
3 0

Answer: Sunlight

Explanation:

The wildflowers bloom early in  the morning in order to get maximum sunlight. The wild flowers bloom early in spring season so as to get optimum amount of sunlight which they require for its growth.

In the later period of spring, the rest of the plants grow and then there is a competition in the plants for the sunlight.

Hence, to avoid the competition for sunlight the wildflowers grows early in the spring season.

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What are the [H₃O⁺] and the pH of a buffer that consists of 0.20 M HF and 0.25 M KF (Kₐ of HF = 6.8X10⁻⁴)?
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The pH of 0.20 M HF (Hydrofluoric acid) is 3.27.  Whereas, [H₃O⁺] for the same is 6.8 X10 ⁻⁴

<h3>What is Hydrofluoric acid?</h3>

A hydrogen fluoride and water solution is hydrofluoric acid. HF solutions are colorless, corrosive, and acidic. The majority of fluorine-containing chemicals are made using it; examples include the substance PTFE and the widely used psychiatric drug fluoxetine. Aluminum, plastics, electrical components, pharmaceuticals, high-octane fuel, fluorescent light bulbs, and refrigerants are all made with hydrogen fluoride. The production of refrigerants uses 60% of the hydrogen fluoride used in manufacturing. corrosive due to the acid's H+ ions and poisonous due to the fluoride ions F-, which can penetrate deeply, chelate calcium and magnesium, and thus upset biological balances due to the destruction of the skin's or an eye's outermost layer.

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2 years ago
Complete this sentence. If mass remains the same while the volume of a substance ________, the density of the substance will____
9966 [12]

Answer:

If mass remains the same while the volume of a substance changes, the density of the substance will also change.

4 0
3 years ago
Which number shows the magma chamber?<br> O 1<br> O 2<br> O 3<br> O4
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8 0
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The combustion of ammonia in the presence of excess oxygen yields no2 and h2o: 4 nh3 (g) + 7 o2 (g) → 4 no2 (g) + 6 h2o (g) the
marshall27 [118]
The combustion of ammonia in presence of excess oxygen yields NO2 and H2O.
The molar mass of ammonia is 17.02 g/mol
Therefore, moles of ammonia in 43.9 g
          = 43.9 /17.02
          = 2.579 moles
From the equation the mole ratio of ammonia to nitrogen iv oxide is 4:4
The molar mass of NO2 is 46 g/mol
The number of moles of NO2 is the same as that of ammonia since they have equal ratio,
 = 2.579 moles
Therefore, mass of NO2
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3 0
4 years ago
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Furkat [3]

Answer:)

1. d

2.c

3.c

4.b

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