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3 years ago

5

Plzzzz help me with one and two I don’t understand

1 answer:

Ratling [72]3 years ago

7 0

What this question simply asks about is you write the numbers it gave you in only one digit by 10 to the power of n. Where n represents the number of shifts of the decimal point.
And to get this number to be one digit, then you have to approximate.
To approximate; you should always consider that less than 5 counts zero and 5 or more counts+1.
Example:
5.3 is approximately 5
5.5 is approx. 6
5.9 is also approx. 6
and so on.
So the final answers are;
1) 4*10^13
2) 5*10^-11
Please note that 10^positive integer will cause the decimal point to move to the right which means a number greater than 1, usually, while 10^negative integer means number smaller than 1, usually.
Hope this helps.

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fgiga [73]

Answer:

The answer is 20 hamburgers and 25 hot dogs.

20(.5)+25(.25)<16.5

10+6.25<16.5

16.25<16.5

The budget is $16.50 and $16.25 is $.50 less therefore making it a possible option for Enrique.

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3 years ago

7/10 write the number as hundredths in a fraction form and decimal form

klemol [59]

7/10 as hundredths decimal: .07

7/10 as fraction: 7/100

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2 years ago

A box contains 3 green marbles, 5 blue marbles, and 7 red marbles. Three marbles are selected at random from the box, one at a t

USPshnik [31]

Answer:

The probability is $P(K) = \frac{ 28 }{195}$

Step-by-step explanation:

From the question we are told that

The number of green marbles is $n_g = 3$

The number of red marbles is $n_b = 5$

The number of red marbles is $n_r = 7$

Generally the total number of marbles is mathematically represented as

$n_t = n_r + n_g + n_ b$

$n_t = 7 + 3 + 5$

$n_t = 5$

Generally total number of marbles that are not red is

$n_k = n_g + n_ b$

=> $n_k = 3 + 5$

=> $n_k = 8$

The probability of the first ball not being red is mathematically represented as

$P(r') = \frac{n_k}{n_t}$

=> $P(r') = \frac{ 8}{15}$

The probability of the second ball not being red is mathematically represented as

$P(r'') = \frac{n_k - 1}{n_t -1}$

=> $P(r'') = \frac{ 8 -1 }{15-1}$ (the subtraction is because the marbles where selected without replacement )

=> $P(r'') = \frac{ 7 }{14}$

The probability that the first two balls is not red is mathematically represented as

$P(R) = P(r') * P(r'')$

=> $P(R) = \frac{ 8}{15} * \frac{ 7 }{14}$

=> $P(R) = \frac{ 8 }{30}$

The probability of the third ball being red is mathematically represented as

$P(r) = \frac{n_r}{ n_t -2}$ (the subtraction is because the marbles where selected without replacement )

$P(r) = \frac{7}{ 15 -2}$

=> $P(r) = \frac{7}{ 13}$

Generally the probability of the first two marble not being red and the third marble being red is mathematically represented as

$P(K) = P(R) * P(r)$

$P(K) = \frac{ 8 }{30} * \frac{7}{ 13}$

=> $P(K) = \frac{ 28 }{195}$

6 0

3 years ago

Can anyone help with this? I will mark you as brainliest!

Pavel [41]

Answer:

1.25x10^2

Step-by-step explanation:

5x5^2

5x5x5=125

125=1.25x10^2

Therefore 5x5^2=1.25x10^2

7 0

3 years ago

Read 2 more answers

Suppose y varies directly with x and y=72 when x=6. what direct variation equation relates x and y? what is the value of y when

scoundrel [369]

Y=12x
Check: 72=12(6)
72=72
y=12x
y=12(10)
y=120
when x is 10 y is 120

6 0

2 years ago

Read 2 more answers