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3 years ago

Polarity does NOT influence physical and chemical properties of a molecule.

Chemistry

1 answer:

lara [203]3 years ago

8 0

False

Explanation:

Polarity does influence the physical and chemical properties of a molecule.

Polarity is the separation of charges in a molecule or compounds.

Polarity influences a lot of inter-molecular bond most especially the vander waals forces. When these bonds are broken, they come with changes in the physical properties of a compound.

Some of the physical properties as a result of polarity are:

Boiling point
Melting point
Surface tension e.t.c

Polarity is a physical property.

Learn more:

Physical property brainly.com/question/10972073

#learnwithBrainly

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What is a flammable mixture of many different substances

Wittaler [7]

The correct answer you are looking for is napalm

Hope this helps!

5 0

3 years ago

In fossil comparisons, it helps to know about similar:

omeli [17]

Answer:

Fossils tell us when organisms lived, as well as provide evidence for the Fossils are the preserved remains or traces of animals, plants, and other organisms from the past. Fossils, by comparing the anatomies of both modern and extinct species, allows scientists to study the skin, hair, and organs of ancient creatures.

Explanation:

6 0

3 years ago

How many Joules are released to cool 250.0 grams of liquid water from 100°C to 0°C? The specific heat of water is 4.180 J/g.C.

nlexa [21]

$\bold{\huge{\orange{\underline{ Solution}}}}$

$\bold{\underline{ Given :- }}$

We have 250g of liquid water and it needs to be cool at temperature from 100° C to 0° C
Specific heat of water is 4.180J/g°C

$\bold{\underline{ To \: Find :- }}$

We have to find the total number of joules released.

$\bold{\underline{ Let's \:Begin:- }}$

We know that,

Amount of heat energy = mass * specific heat * change in temperature

That is, 

$\sf{\red{ Q = mcΔT }}$

Subsitute the required values in the above formula :-

$\sf{ Q = 250 × 4.180 ×(0 - 100 )}$

$\sf{ Q = 250 × 4.180 × - 100 }$

$\sf{ Q = 250 × - 418}$

$\sf{\pink{ Q = - 104,500 J }}$

Hence, 104,500 J of heat is released to cool 250 grams of liquid water from 100° C to 0° C.

$\bold{\underline{ Now :- }}$

We have to tell whether the above process is endothermic or exothermic :-

Here, In the above process ΔT is negative and as a result of it Q is also negative that means above process is Exothermic

Exothermic process :- It is the process in which heat is evolved .
Endothermic process :- It is the process in which heat is absorbed .

4 0

2 years ago

Which compound plays an important role in leather processing and electroplating?

Margaret [11]

Answer;

Hydrochloric acid

Explanation;

Hydrochlorc acid plays a vital role in leather processing and electroplating.
Hydrochloric acid has a number of important applications in real life these includes; fertilizers, and dyes, textile, in electroplating, rubber and in the photographic industries.
Electroplating is the process that involves coating a metal using another metal for the purpose of improving their appearance or preventing rusting.
Hydrochloric acids is used in the processing of leather or the tanning of leather process, in which tanneries use the acid to stop the growth of bacteria and also maintain proper pH.

7 0

3 years ago

Read 2 more answers

For each of the following pairs of complexes, identify which one you would predict to have the larger Δo value, and explain why.

mash [69]

Answer:

a) [Fe(H2O)6]3+

b) [Fe(CN)6]3−

c) [Ru(CN)6]3-

Explanation:

. [Mn(H2O)6]2+ or [Fe(H2O)6]3+

The both complexes are d5 complexes with the same ligand , water. Water is a weak ligand and note that Mn^2+ often have a crystal field stabilization energy of zero hence

[Fe(H2O)6]3+ will possess a greater ∆o value.

The splitting of d orbitals according to the crystal field theory depends on the;

i)geometry of the complex

ii) nature of the metal ion,

iii)charge on the metal ion,

iv) ligands that surround the metal ion.

When the geometry and the ligands are held constant, the order of crystal field splitting is as follows;

Pt4+ > Ir3+ > Rh3+ > Co3+ > Cr3+ > Fe3+ > Fe2+ > Co2+ > Ni2+ > Mn2+

[Fe(H2O)6]3+ or [Fe(CN)6]3−

[Fe(CN)6]3− will have a greater ∆o because the cyanide ion is a strong field ligand compared to water. A strong field ligand causes a greater splitting of the octahedral crystal field compared to a weak field ligand.

. [Fe(CN)6]3− or [Ru(CN)6]3-

[Ru(CN)6]3- will exhibit a greater crystal field splitting. Crystal field splitting increases with the second and third row transition elements when compared to the crystal field splitting of the first row transition elements. Note that, there is an increase of approximately 30%–50% in Δo on going from a first-row transition metal to a second-row metal and another 30%–50% increase on going from a second-row to a third-row metal when they have the same geometry and oxidation state.

4 0

3 years ago