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3 years ago

A student is interested in resource recovery through composting. Which field

1 answer:

4 0

I think it’s microbiology, since it would help the student understand the process of composting the best. Botany is plants- not for composting. Geophysics- he’s not researching tectonic plates. Oceanography- he isn’t interested in the marina trench

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What mass of ether will be produced is 221 g of ethanol reacts with a 66 percent yield?

Keith_Richards [23]

@pandamille help her please!!!!

5 0

3 years ago

When iron metal reacts with sulfuric acid, it produces iron (III) sulfate and hydrogen gas. Balance the equation: Fe + H2SO4 → F

aleksklad [387]

2Fe + 3H2SO4 → Fe2(SO4)3 + 3H2

Explanation:

Changing the subscripts changes the products of the equation

7 0

2 years ago

A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f

a_sh-v [17]

Answer:

$m_{H_2O}=39.0g$

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

$\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})$

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

$m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g$

Best regards.

8 0

3 years ago

Hurry please!

Pani-rosa [81]

Answer : The mass of of water present in the jar is, 298.79 g

Solution : Given,

Mass of barium nitrate = 27 g

The solubility of barium nitrate at $20^oC$ is 9.02 gram per 100 ml of water.

As, 9.02 gram of barium nitrate present in 100 ml of water

So, 27 gram of barium nitrate present in $\frac{27g}{9.02g}\times 100ml=299.33ml$ of water

The volume of water is 299.33 ml.

As we know that the density of water at $20^oC$ is 0.9982 g/ml

Now we have to calculate the mass of water.

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}$

$\text{Mass of water}=(0.9982g/ml)\times (299.33ml)=298.79g$

Therefore, the mass of of water present in the jar is, 298.79 g

5 0

3 years ago

The reaction below will occur in a gaseous system at STP:

WARRIOR [948]

Answer:

V = 12.5 L

Explanation:

Given data:

Volume of NO = 15.0 L

Temperature and pressure = standard

Volume of nitrogen gas produced = ?

Solution:

Chemical equation:

6NO + 4NH₃ → 5N₂ + 6 H₂O

Number of moles of NO:

PV = nRT

n = PV/RT

n = 1 atm × 15.0 L / 0.0821 atm.L /mol.K × 273.15 K

n = 15.0 atm.L / 22.43 atm.L /mol

n = 0.67 mol

now we will compare the moles of No and nitrogen gas.

NO : N₂

6 : 5

0.67 : 5/6×0.67 = 0.56

Volume of nitrogen gas:

PV = nRT

1 atm × V = 0.56 mol × 0.0821 atm.L /mol.K × 273.15 K

V = 12.5 atm.L / 1 atm

V = 12.5 L

4 0

3 years ago