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3 years ago

Help!!!plz help me with this question

Chemistry

1 answer:

denpristay [2]3 years ago

3 0

Answer:

<h3>ENVIRONMENT</h3>

Explanation:

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For water at 30C and 1 atm: a= 3.04x10^-4 k^-1 , k =4.52x10^-5 atm ^-1 = 4.46 x10^-10 m^2/N, cpm= 75.3j/9molk), Vm =18.1cm^3/mol

Lapatulllka [165]

Answer:

$C_{vm}$ of water at 30C and 1 atm is 256.834 J/mol·K.

Explanation:

To solve the question, we note the Maxwell relation such as

$C_{pm}-C_{vm}=\frac{9T\alpha ^2 V }{K}$

Where:

$C_{pm}$ = Specific heat of gas at constant pressure = 75.3 J/mol·K

$C_{vm}$ = Specific heat of gas at constant volume = Required

T = Temperature = 30 °C = 303.15 K

α = Linear expansion coefficient = 3.04 × 10⁻⁴ K⁻¹

K = Volume comprehensibility = 4.52 × 10⁻⁵ atm⁻¹

Therefore,

75.3 - $C_v$ = $\frac{9\times 303.15 \times (3.04 \times 10^{-1} 1.81 \times 10^{-5} }{4.52 \times 10^{-5} }$

$C_{vm}$ = $\frac{9\times 303.15 \times (3.04 \times 10^{-1} 1.81 \times 10^{-5} }{4.52 \times 10^{-5} }$ - 75.3 = 256.834 J/mol·K.

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3 years ago

Calculate the wavelength (in nanometers) of a photon emitted by a hydrogen atom when its electron drops from the n = 5 to n = 3

tankabanditka [31]

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3 years ago

If you have 0.045 L of 0.465 M potassium bromide. How many moles of potassium bromide are present?

Mekhanik [1.2K]

The answer to your question is letter A! Hope that helps

7 0

3 years ago

NikAS [45]

Answer:

After you have waived your rights, the confession must still be a voluntary confession. Whether a confession is voluntary or not is based on the “totality of the circumstances”. The Courts have held that a police officer simply lying does not result in an “involuntary confession”.

Explanation:

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3 years ago

Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th

WINSTONCH [101]

<u>Answer:</u> The standard enthalpy change of the reaction is coming out to be -16.3 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]$

We are given:

$\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ$

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

6 0

3 years ago

Help!!!plz help me with this question ​

Help!!!plz help me with this question