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Virty [35]
2 years ago
10

Help!!!plz help me with this question ​

Chemistry
1 answer:
denpristay [2]2 years ago
3 0

Answer:

<h3>ENVIRONMENT</h3>

Explanation:

I HOPE IT HELPS :)

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What is the most reactive metal in Period 4 of the periodic table?
kykrilka [37]

Answer:

Potassium

Explanation:

5 0
2 years ago
Today's demand curve for gasoline could shift in response to a change ina.today's price of gasoline. b.the expected future price
Nimfa-mama [501]

Answer:

d.All of the above are correct.

Explanation:

The curve of demand moves left or right continuously. Income, patterns and preferences, related products prices as well as the population size and composition are the key factors causing demand change.

3 0
2 years ago
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A 54-kg jogger is running at a rate of 3 m/s. What is the kinetic energy of the jogger
Phantasy [73]
Kinetic energy = 1/2mv²
where m = 54kg
and v =3m/s
k.e = 1/2×54×3×3
= 1/2×54×9
= 1/2×426
= 486÷2
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please mark as brainliest
4 0
3 years ago
Consider the equilibrium
vladimir1956 [14]

Answer:

Kp^{1000K}=0.141\\Kp^{298.15K}=2.01x10^{-18}

\Delta _rG=1.01x10^5J/mol

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

C_2H_6(g)\rightleftharpoons H_2(g)+C_2H_4(g)

Thus, Kp for this reaction is computed based on the given molar fractions and the total pressure at equilibrium, as shown below:

p_{C_2H_6}^{EQ}=2bar*0.592=1.184bar\\p_{C_2H_4}^{EQ}=2bar*0.204=0.408bar\\p_{H_2}^{EQ}=2bar*0.204=0.408bar

Kp=\frac{p_{C_2H_4}^{EQ}p_{H_2}^{EQ}}{p_{C_2H_6}^{EQ}}=\frac{(0.408)(0.408)}{1.184}=0.141

Now, by using the Van't Hoff equation one computes the equilibrium constant at 298.15K assuming the enthalpy of reaction remains constant:

Ln(Kp^{298.15K})=Ln(Kp^{1000K})-\frac{\Delta _rH}{R}*(\frac{1}{298.15K}-\frac{1}{1000K} )\\\\Ln(Kp^{298.15K})=Ln(0.141)-\frac{137000J/mol}{8.314J/mol*K} *(\frac{1}{298.15K}-\frac{1}{1000K} )\\\\Ln(Kp^{298.15K})=-40.749\\\\Kp^{298.15K}=exp(-40.749)=2.01x10^{-18}

Finally, the Gibbs free energy for the reaction at 298.15K is:

\Delta _rG=-RTln(Kp^{298.15K})=8.314J/mol*K*298.15K*ln(2.01x10^{-18})\\\Delta _rG=1.01x10^5J/mol

Best regards.

3 0
3 years ago
NEED THIS NOW!! !!
gavmur [86]

Answer:

D: It must stay the same

Explanation:

The Law of Conservation of Mass states that when matter changes form (B.E.C., solid, liquid, gas, plasma), no particles are created or destroyed.

This makes a change in mass impossible, since the atoms themselves stay the same.

The state of matter is independent of the mass of any atom.

3 0
3 years ago
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