Three times a number increased by 8 is no more than the number decreased by 4.find the number
1 answer:
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1.) c. x^2−2x+4−14/x+2
2.) The remainder is 1/2x-1. When you divide 8x^2+4x−3 by 2x-1, your answer is 4x+4 remainder 1/2x-1.
3.)The remainder is 6/(x+3) because when you divide 7x^2+15x−12 by x+3, you get 7x-6 remainder 6/x+3
The work is attached if you need it, sorry for the messiness!
