A +2.2 x 10-9 C charge is on the axis ar x= 1.5 m, a +5.4 x 10-9 C charge is on the x-axis at x= 2.0 m, and a+3.5 x 10-9 C charg e is at the origin. find the net force on the charge at the origin
1 answer:
The net force on the charge at the origin is -1.2×10-8
<u>Explanation: </u>
Solving the problem,
Draw the x-axis and the locations of the given three charges. The forces applied on the charge at the origin and there are two of them, and since all the changes are positive, all the forces are repulsive. we have the formula, F = kq1Q/r². F1 = kq1Q/r²1 = (9.0*109Nm²/C²)(2.2*10^-9C)(3.5*10^-9C)/(1.5m)² = 31*10-9N = 3.1*10-8N. F1 points to the right (+x direction). F2 = kq2Q/r²2 = (9.0*109Nm²/C²)(5.4*10^-9C)(3.5*10^-9C)/(2.0m)² = 43*10^-9N = 4.3*10^-8N. F2 points to the left (-x direction). To find the net force we have to subtract the force F1 and force F2 . The net force is F(origin) = F1 - F2 = -1.2×10-8N. <u> </u>
<u> </u>
<u> </u>
<u> </u>
You might be interested in
Answer: In a chemical reaction blank are the substances left over
Explanation: The substance left over after a reaction takes place
Answer:
22600 cm³ (3 s.f.)
Explanation:
Please see the attached picture for the full solution.
<span>Last choice on the list: Object A has a net charge of 0 because the positive and negative charges are balanced. Object B has a net charge of –2 because there is an imbalance of charged particles (2 more negative electrons than positive protons).</span>
Bdjsbevevfbfcnbfbffbs s kdkfc
Answer:
D. You speed up
Explanation:
hope it helps