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ratelena [41]
3 years ago
9

Which of the following scenarios is possible for the resultant velocity of an airplane in a strong wind to be 150 m/s?

Physics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer:

B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.

Explanation:

From Physics we get that resultant velocity of an airplane is the sum of an absolute velocity and a relative velocity, that is:

\vec v_{A} = \vec v_{W}+\vec v_{A/W} (Eq. 1)

Where:

\vec v_{W} - Wind velocity, measured in meters per second.

\vec v_{A/W} - Airplance velocity relative to wind, measured in meters per second.

\vec v_{A} - Airplane velocity, measured in meters per second.

If we assume that \vec v_{W} = 20\,\hat{i}\,\,\,\left[\frac{m}{s} \right] (The airplane flies with the wind), \vec v_{A/W} = 130\,\hat{i}\,\,\,\left[\frac{m}{s} \right], then the resultant velocity of the airplane is:

\vec v_{A} = 20\,\hat{i}+130\,\hat{i}\,\,\,\left[\frac{m}{s} \right]

\vec v_{A} = 150\,\hat{i}\,\,\,\left[\frac{m}{s} \right]

Therefore, correct answer is B.

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Delvig [45]

Answer:

Increase in the temperature of water would be 0.9 degree C

Explanation:

As we know by energy conservation

Change in the gravitational potential energy of the cylinder = increase in the thermal energy of the water

Here we know that the gravitational potential energy of the cylinder is given as

U = mgh

here we have

h = 300 m

now we can say

Mc\Delta T = (m \times 9.8 \times 300)

now if the cylinder falls from height h = 100 m

then we have

Mc\Delta T' = (m \times 9.8 \times 100)

now from above two equations

\frac{\Delta T'}{\Delta T} = \frac{100}{300}

\Delta T' = 2.7 \times \frac{1}{3} = 0.9 Degree C

8 0
3 years ago
The weight of spaceman Speff at the surface of planet X, solely due to its gravitational pull, is 389 N. If he moves to a distan
miv72 [106K]

Answer:

mass of the planet X = 5.6 × 10²³ kg.

Explanation:

According to Newtons law of universal gravitation,

F = GM₁M₂/r²

Where F = gravitational force, M₁ = mass of the speff, M₂ = mass of the planet X, G = gravitational constant r = distance between the speff and the planet X

making M₂ The subject of the equation above,

M₂ = Fr²/GM₁ .......................... equation 2

Where F = 24.31 N, r = 1.08×18⁴km ⇒( convert to m ) =1.08 × 10⁴  × 1000 m

r = 1.08  × 10⁷ m, G = 6.67  × 10 ⁻¹¹ Nm²/kg², M₁ = 75 kg

Substituting this values in equation 2,

M₂ = 24.13(1.08  × 10⁷ )²/75( 6.67  × 10 ⁻¹¹)

M₂ = 24.13 × 1.17 × 10¹⁴/500.25 × 10⁻¹¹

M₂ = (28.23 × 10¹⁴)/(500.25 × 10⁻¹¹)

M₂ = 0.056 × 10²⁵

M₂ = 5.6 × 10²³ kg.

Therefore mass of the planet X = 5.6 × 10²³ kg.

8 0
3 years ago
Hilda plans to display in a clear cube the needle betsy ross used to sew the first american flag. the needle will fit exactly as
inysia [295]

Based on the length of side of the cube given, the length of the needle is 2.28 inches.

<h3>What is the length of the needle?</h3>

The length of the side of a cube and its diagonal are related by the formula below:

Length \:  of \:  Diagonal = \sqrt{3s}

where s is length of side

Side \:  Length  \: of \:  the \:  Cube = \sqrt{3inches}

Diagonal \: of  \: a  \: face \:  of  \: the \: cube = \sqrt{6inches}

The \: length \: of \: the \: needle = \sqrt{3\sqrt{3}}  = 2.28 \: inches \\

Therefore, the length of the needle is 2.28 inches

Learn more about length of diagonal of cube at: brainly.com/question/800212

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8 0
2 years ago
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Ball 1 travels with a momentum of 48.0 kg-m/s east and strikes Ball 2, which is initially at rest.. Ball 1 separates at an angle
vladimir1956 [14]

Answer:

Momentum of 2nd ball is

P = 31.6 kg m/s

direction is given as

\theta = -37.66 degree

Explanation:

As we know that there is no external force on the system of balls so momentum before and after collision will be conserved

So we have

P_i = 48 \hat i + 0

now after collision momentum of two balls is must be same as initial

so we have

P_i = P_f

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for other component we have

0 = 19.3 + P_{2y}

P_{2y} = -19.3 kg m/s

Momentum of 2nd ball is given as

P = \sqrt{P_2x}^2 + P_{2y}^2}

P = 31.6 kg m/s

direction is given as

tan\theta = \frac{P_{2y}}{P_{2x}}

tan\theta = \frac{-19.3}{25}

\theta = -37.66 degree

5 0
3 years ago
What happens when the object is placed at F? Explain<br> your answer.
34kurt

Answer:

Sample Response: No image will be formed because the rays will not converge to or diverge from a common point.

Explanation:

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