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ratelena [41]
3 years ago
9

Which of the following scenarios is possible for the resultant velocity of an airplane in a strong wind to be 150 m/s?

Physics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer:

B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.

Explanation:

From Physics we get that resultant velocity of an airplane is the sum of an absolute velocity and a relative velocity, that is:

\vec v_{A} = \vec v_{W}+\vec v_{A/W} (Eq. 1)

Where:

\vec v_{W} - Wind velocity, measured in meters per second.

\vec v_{A/W} - Airplance velocity relative to wind, measured in meters per second.

\vec v_{A} - Airplane velocity, measured in meters per second.

If we assume that \vec v_{W} = 20\,\hat{i}\,\,\,\left[\frac{m}{s} \right] (The airplane flies with the wind), \vec v_{A/W} = 130\,\hat{i}\,\,\,\left[\frac{m}{s} \right], then the resultant velocity of the airplane is:

\vec v_{A} = 20\,\hat{i}+130\,\hat{i}\,\,\,\left[\frac{m}{s} \right]

\vec v_{A} = 150\,\hat{i}\,\,\,\left[\frac{m}{s} \right]

Therefore, correct answer is B.

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Problem 1 Observer A, who is at rest in the laboratory, is studying a particle that is moving through the laboratory at a speed
ANTONII [103]

Answer:

markers are 29.76 m far apart in the laboratory

Explanation:

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we know that

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distance = 0.624c × 1.59 × 10⁻⁷ s

distance = 0.624(3 × 10⁸ m/s) × 1.59 × 10⁻⁷ s

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Explanation:

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