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ratelena [41]
3 years ago
9

Which of the following scenarios is possible for the resultant velocity of an airplane in a strong wind to be 150 m/s?

Physics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer:

B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.

Explanation:

From Physics we get that resultant velocity of an airplane is the sum of an absolute velocity and a relative velocity, that is:

\vec v_{A} = \vec v_{W}+\vec v_{A/W} (Eq. 1)

Where:

\vec v_{W} - Wind velocity, measured in meters per second.

\vec v_{A/W} - Airplance velocity relative to wind, measured in meters per second.

\vec v_{A} - Airplane velocity, measured in meters per second.

If we assume that \vec v_{W} = 20\,\hat{i}\,\,\,\left[\frac{m}{s} \right] (The airplane flies with the wind), \vec v_{A/W} = 130\,\hat{i}\,\,\,\left[\frac{m}{s} \right], then the resultant velocity of the airplane is:

\vec v_{A} = 20\,\hat{i}+130\,\hat{i}\,\,\,\left[\frac{m}{s} \right]

\vec v_{A} = 150\,\hat{i}\,\,\,\left[\frac{m}{s} \right]

Therefore, correct answer is B.

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vovikov84 [41]

Answer:

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putting the values into the formula above;

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0 + 0.5mu² = 50m + 264.5m

0.5mu² = 314.5m

dividing through by m

0.5u² = 314.5

u² = 629

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<u>Theref</u><u>ore</u><u>,</u><u> </u><u>the</u><u> </u><u>init</u><u>ial</u><u> </u><u>speed</u><u> </u><u>"</u><u>u</u><u>"</u><u> </u><u>=</u><u> </u><u>2</u><u>5</u><u>m</u><u>/</u><u>s</u>

6 0
3 years ago
What will occur when the waves peak at the same place at the same time?
dedylja [7]
Hello!

This is a matter of superposition.
When the waves peak at the same time and place, they produce constructive interference, meaning the waves interact together in a positive way, to make a wave with Amplitude of both waves added together. When the peaks differ however, at the same time and place, then it is destructive interference and the waves essentially cancel each other out.

Hope this helps. Any questions please just ask. Thank you kindly.
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Three cars (car F, car G, and car H) are moving with the same velocity when the driver suddenly slams on the brakes, locking the
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Answer:

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Explanation:

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m = mass

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From the formula above, we see that frictional force is dependent on the mass of object and the coefficient of friction.

Since they all have the same tires, the coefficient of friction between the tire and the floor is the same for each car. Acceleration due to gravity, g, is constant.

The only factor that determines the frictional force of each car is the mass. Hence, the more the mass, the more the frictional force.

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5 0
3 years ago
It takes 160 kj of work to accelerate a car from 24.0 m/s to 27.5 m/s. what is the car's mass?
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W = 1/2 m ( Vf^2 -Vo^2 )
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Explanation:
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