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erastovalidia [21]
2 years ago
10

Given that ethylene has a λmax of 175nm, butadiene has a λmax of 220nm, and 2-methyl-1,3-butadiene has a λmax or 215nm, what is

the λmax of 2,3,4-trimethylhexatriene?
Physics
1 answer:
Vika [28.1K]2 years ago
5 0

The λmax of 2,3,4-trimethylhexatriene is 280 nm.

Ethylene has a λmax of 175nm.

Butadiene has a λmax of 220nm.

2-methyl-1,3-butadiene has a λmax or 215nm.

1,3,5-hexatriene has a λmax of 258nm.

Woodward's rules, sometimes known as Woodward-Fieser rules (after Louis Fieser) and named after Robert Burns Woodward, are a number of sets of empirically developed principles that aim to forecast the wavelength of the absorption maximum (max) in an ultraviolet-visible spectrum of a certain molecule.

By using the Woodward Fieser rule,

R- (Alkyl Group) .... +5 nm = 5 × 2 = 10

RO- (Alkoxy Group) .. +6 = 6 × 2 = 12

Adding 22nm to the λmax of 1,3,5-hexatriene as it has 2 alkyl groups and 2 alkoxy groups to form 2,3,4-trimethylhexatriene.

The λmax of 2,3,4-trimethylhexatriene is 280 nm.

Learn more about Woodward-Fieser here:

brainly.com/question/16982345

#SPJ4

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the diagram below shows a segment of DNA before and after erplication, which of the following could have occured as a result of
Lorico [155]

The change or mutation in a segment of DNA after replication may lead to changes in the genotype, the traits of the organism and the proteins (option i, ii and iii).

<h3>What is a genetic mutation?</h3>

A genetic mutation is any change in the nucleotide bases of the genome of an organism that may be associated with modifications in the phenotypic traits or features of the organism if this change alters the expression of a given gene that produces a particular protein.

Mutations may be neutral when they don't show an apparent effect on the phenotype of an organism such as occur in mutations located in intergenic regions.

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8 0
1 year ago
A satellite m-500 kg orbits the earth at a distance d 215 km, above the surface of the planet. The radius of the earth is re 6.3
AnnZ [28]

Answer:

7.78 * 10³ m/s

Explanation:

Orbital velocity is given as:

v = √(GM/R)

G = 6.67 * 10^(-11) Nm/kg²

M = 5.98 * 10^(24) kg

R = radius of earth + distance of the satellite from the surface of the earth

R = 2.15 * 10^(5) + 6.38 * 10^(6)

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v = √([6.67 * 10^(-11) * 5.98 * 10^(24)] / 6.595 * 10^(6))

v = √(6.048 * 10^7)

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