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Fittoniya [83]
2 years ago
14

1. A 700kg racecar slowed from 30m/s to 15 m/s. What was its change in Momentum? 2. If the car in the above problem took 5 secon

ds to slow down from 30m/s to 15 m/s. a. What is the impulse? b. What was the average force applied by the brakes?
Physics
1 answer:
s2008m [1.1K]2 years ago
6 0
1. The change in momentum follows the formula:

Change in Momentum = mΔv,
where m is the mass and v is the velocity

Change in momentum = (700 kg)(15 m/s - 30 m/s) =<em> -10,500 kg·m/s</em>

2. For this problem, the formula for impulse, J, is

J = FΔt

Before answering part a, we answer for part b first.

Part B. 
F = ma
where
a = Δv/t = (15 - 30)/5 = -1 m/s²
So,
F = (700 kg)(-1 m/s²) = <em>-700 N</em>

Part A.
J = (-700 N)(5 s) =<em> -3,500 N·s</em>
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A television weighs 8.50 pounds. How many grams is this? (Hint: You need to
Ksenya-84 [330]

Answer:

3859 grams

Explanation:

Given: Weight of a television = 8.50 pounds

To find: Weight of a television in grams

Solution:

1 pound = 0.454 kg and 1 kg = 1000 g

So,

1 pound = 0.454 × 1000 = 454 grams

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7 0
3 years ago
An eagle flying at 15 m/s has 600 J of kinetic energy. About how much is the eagles mass?
Eduardwww [97]

Answer:

5.33kg

Explanation:

Given parameters:

Velocity of eagle  = 15m/s

Kinetic energy of the eagle = 600J

Unknown:

Mass of the eagle  = ?

Solution:

The kinetic energy of any body is the energy due to the motion of a body. There are different forms of kinetic energy some of which are thermal, mechanical, electrical  energy.

The formula of kinetic energy is given as;

              Kinetic energy  = \frac{1}{2} m v²

where m is the mass, V is the velocity

   substitute the parameters in the equation;

                       600  = \frac{1}{2} x m x 15²

                     225m  = 1200

                            m  = \frac{1200}{225}    = 5.33kg

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2 years ago
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Varvara68 [4.7K]

Answer:

point c

Explanation:

the cart has accelerated and is at the lowest point on the path .

consider the acceleration due to gravity converting potential to kinetic energy

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