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g100num [7]
3 years ago
15

Some students decide to plant their own garden. They want to eat a more plant-based diet For meat, they will buy locally from a

butcher. Any remaining scraps will be composted and used as fertilizer for their garden Which part of this plan represents recycling to reduce their waste?
composting scraps

planting a garden

eating a plant-based diet

buying locally
Chemistry
1 answer:
ozzi3 years ago
7 0

Answer:

composting scraps

recycling is the action or process of converting waste into reusable material.

You might be interested in
Which of these statements describes this mathematical equation?
salantis [7]

Answer:

The final pressure of a gas is inversely proportional to the volume change and directly proportional to temperature

Explanation:

Given

\frac{P_1V_1}{T_1} = k

Required

Interpret

\frac{P_1V_1}{T_1} = k

Multiply both sides by T1

T_1 * \frac{P_1V_1}{T_1} = k * T_1

P_1V_1 = kT_1

Divide both sides by V1

\frac{P_1V_1}{V_1} = \frac{kT_1}{V_1}

P_1 = \frac{kT_1}{V_1}

This can be rewritten as:

P_1 = k\frac{T_1}{V_1}

In the above expression; k is a constant of proportionality.

So, the equation can be written as variation as follows:

P_1\ \alpha\ \ \frac{T_1}{V_1}

To interpret:

<em>P varies directly to T (the numerator) and inversely to V (the denominator).</em>

<em></em>

3 0
3 years ago
Determine the mass of carbon iv oxide ,produced on burning 104g of ethyne​
mars1129 [50]

163 grams (3 sig. fig.).

<h3>Explanation</h3>
  • Formula of <em>carbon(IV) oxide</em> (a.k.a. carbon dioxide): \text{CO}_2.
  • Molar mass of \text{CO}_2: \underbrace{12.01}_{\text{C}} + 2\times\underbrace{16.00}_{\text{O}}=44.01\;\text{g}\cdot\text{mol}^{-1}.
  • Formula of ethyne: structural \text{H}-\text{C}\equiv\text{C}-\text{H} or molecular \text{C}_2\text{H}_2.
  • Molar mass of \text{C}_2\text{H}_2: 2\times\underbrace{12.01}_{\text{C}}+2 \times\underbrace{16.00}_{\text{O}} = 56.02\;\text{g}\cdot\text{mol}^{-1}.

All carbon atoms in that 104 grams of ethyne will end up in \text{CO}_2. Number of moles of molecules in 104 grams of ethyne:

n = \dfrac{m}{M} = \dfrac{104}{56.02} = 1.85648\;\text{mol}.

There are two carbon atoms in each ethyne molecule. Number of carbon atoms in that many ethyne molecules:

n(\text{C}) = 2\;n(\text{C}_2\text{H}_2) = 3.71296\;\text{mol}.

There are one carbon atom in each \text{CO}_2 molecule. In case oxygen is in excess, all those carbon atoms from that 104 grams of ethyne will make n(\text{CO}_2) = n(\text{C}) =3.71296\;\text{mol} of \text{CO}_2.

Mass of all those \text{CO}_2 molecules:

m = n\cdot M = 163\;\text{g}. (3 sig. fig. as in the mass of ethyne.)

7 0
4 years ago
If 5.00 mL of 1.00 M HCl is used to titrate the hydroxide ion produced by a piece of Sodium, What mass of Sodium is used in gram
suter [353]

Answer:

Explanation:

Equation of the reaction:

NaOH + HCl --> NaCl + H2O

Volume of HCl = 5 ml

Molar concentration = 1 M

Number of moles = molar concentration * volume

= 1 * 0.005

= 0.005 mol of HCl

By stoichiometry, 1 mole of HCl completely neutralizes 1 mole of NaOH

Therefore, number of moles of NaOH = 0.005 mol

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

NaOH --> Na+ + OH-

Mass = molar mass * number of moles

= 40 * 0.005

= 0.2 g of Na+

6 0
3 years ago
The total number of electrons in the outer shell of a sodium atom is?<br>A. 1<br>B.2<br>C.8<br>D.18​
mrs_skeptik [129]

Answer:

1

Explanation:

outershell atoms of an element are also known as valency of that element

so the valency and number of elctron in the outershell of a sodium atom is +1.

hope this will help

mark me as brilliant

7 0
3 years ago
If a gas in a closed container is pressurized from 15.0 atmospheres to 16.0
Yuki888 [10]

Answer:

T₂ = 317.87 K

Explanation:

Given data:

Initial pressure = 15 atm

Final pressure = 16 atm

Initial temperature = 298 K

Final temperature = ?

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

15 atm / 298K = 16 atm/T₂

T₂ = 16atm × 298 K / 15 atm

T₂ = 4768 atm. K / 15 atm

T₂ = 317.87 K

4 0
3 years ago
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