Answer:
The entropy change for the vaporization of 18 grams of a hydrocarbon at its boiling point is 12.87 J/K.
Explanation:
Mass of hydrocarbon = 18 g
Molar mass of hydrocarbon = 114 g/mol
Moles of hydrocarbons =
The enthalpy of vaporization of hydrocarbon =
Heat required to heat 0.1579 moles of hydrocarbon = Q
Q = 4.263 kJ = 4,263 J ( 1 kJ = 1000 J)
Boiling point of hydrocarbon = T = 58.2°C = 58.2 + 273 K = 331.2 K
Entropy change for the vaporization of 18 g of a hydrocarbon:
The entropy change for the vaporization of 18 grams of a hydrocarbon at its boiling point is 12.87 J/K.
Answer: (c)
Explanation:
Nuclear fusion reactions involve 2 smaller nuclides combining to form one larger nuclide.
However, the mass is not correctly balanced for (a), but it is for (c).
Answer:
2Al + 3CuSO4 → Al2(SO4)3 + 3Cu
Explanation:
I THINK
<span>1 The change of matter from a solid state to a gas state is called sublimation.
</span><span>2. When a solute is completely dissolved in a solvent, a solution is formed. (A)
3. Base are used in </span><span>Used in ammonia, Alka-Seltzer, and dish soap
</span><span>
4. </span><span>TRUE . Simple devices lower the required input force.
5. FALSE. It's the opposite.</span>
Answer: The statement is true
Explanation:
The half-life of a radioactive isotope is the time taken for half of the total number of atoms in a given sample of the isotope to decay.
For instance
The half-life of radium is 1622 years. This means that if we have 1000 radium atoms at the beginning, then at the end of 1622 years, 500 atoms would have disintegrated, leaving 500 undecayed radium atoms
Thus, the statement is true