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Y_Kistochka [10]
2 years ago
12

Washing dishes in the dishwasher with detergent and hot water is a ________ process.

Chemistry
1 answer:
RideAnS [48]2 years ago
8 0

Answer:

Washing dishes in the dishwasher with detergent and hot water is a<u> Disinfecting</u>  process.

<u>Explanation:</u>

There is a large number of micro-organisms present on the dishes which are yet to be washed. So when we wash them with detergent and hot water all the dishes get disinfected.

Disinfecting a dish makes it free from various germs present on it. When we disinfect a dish the germs or micro-organisms present are deactivated. This prevents their multiplication. Chemicals like Alcohol chlorine and hydrogen peroxide can be used as a disinfectant.

You might be interested in
How many grams are in 3.93 x 10^24 molecules of CCl4?
Lorico [155]
<h3>Answer:</h3>

1000 g CCl₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.93 × 10²⁴ molecules CCl₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of CCl₄ - 12.01 + 4(35.45) = 153.81 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.93 \cdot 10^{24} \ molecules \ CCl_4(\frac{1 \ mol CCl_4}{6.022 \cdot 10^{23} \ molecules \ CCl_4})(\frac{153.81 \ g \ CCl_4}{1 \ mol \ CCl_4})
  2. Multiply:                                                                                                             \displaystyle 1003.77 \ g \ CCl_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1003.77 g CCl₄ ≈ 1000 g CCl₄

8 0
3 years ago
How much heat is required to raise the temperature of 81.0 g of water from its melting point to its boiling point?
Dovator [93]

Answer:

Specific heat of water = 33.89 KJ

Explanation:

Given:

mass of water = 81 gram

Initial temperature = 0°C

Final temperature = 100°C

Specific heat of water = 4.184

Find:

Required heat Q

Computation:

Q = Mass x Specific heat of water x (Final temperature - Initial temperature)

Q = (81)(4.184)(100-0)

Q = 33,890.4

Specific heat of water = 33.89 KJ

6 0
3 years ago
Type the correct answer in each box.
Arturiano [62]

Answer:

5SiO2 + 2CaC2 = 5Si + 2CaO + 4CO2

Explanation:

balancing equations is a lot of trial and error. My strategy to approaching this equation was to get the O's balanced. After trying several combonations I found that I needed 10 O's on each side of the equation for the other elements to match up. After I balanced the O's, I balanced my C's to 4 on each side. Then I balanced my Ca's to have 2 on each side. And last but not least I balanced my Si to have 5 on each side.

8 0
3 years ago
Is it posible Count a grain of sand?explain
Alla [95]

Answer:

Yes

Explanation:

As long as its a solid, you can count it. It will be hard, but possible.

5 0
3 years ago
Jennie decides to mix the content of her beaker with another lab group to see “the results.” Is this safe why or why not explain
Ray Of Light [21]

Answer: no

Explanation:

It could be dangerous since you don't know what substance are you adding.it may end up in an explosion

I hope this helps :)

6 0
2 years ago
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