Answer:
Width w = 4m
Glow depth = y1 = 20m
Outlet discharge = 40m
V1= velocity of flow = 40/20*4 = 1/2 = 0.5m/s
Froud number = v1/√gy1
= 0.5/√9.81x20 = 0.0356
1. Y2/20 = 1/2[-1+√1+8*(0.0356)²]
Y2 = 0.05
2. Energy loss in the jump = (20-0.05)²/4x20x0.05
= 1985m
Answer:
See the detailed answer in attached file.
Explanation :
Answer:112.376 s
Explanation:
Given






Using Newton's law of cooling
=
=
7=
Taking log both side
t=112.376sec
Answer:
Days: 6.9444 days
Production rate: 547.2035 ft²/s
Explanation:
the solution is attached in the Word file