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xeze [42]
3 years ago
13

An assembly line in a modern business compared to 1 from Henry Ford's time is more likely to rely on which of the following unsk

illed workers sweet sweatshops skilled workers or fix layouts
unskilled workers
sweat shops
skilled workers
fixed layouts
​
Engineering
1 answer:
andrew-mc [135]3 years ago
3 0

In assembly line in a modern business compared to 1 from Henry Ford's time is more likely to rely on - The  unskilled workers

Explanation:

<u>Charles Sorensen</u> is know as the architect of the modern assembly

Henry Ford believed that they can hire an unskilled worker and teach a stage of car production thus reducing its labor cost.

The basic principle of assembly line is that one worker only performs a specific task no multi tasking is involved  and the person continues to repeat the same task again and again and then it moves to the other person  until the task get completed.

<u>Charles Sorensen believed that skilled workers can be engaged in task like planning,management and tool building and not every body has the skills.So we can employ the unskilled workers to work on specialize machinery's it helps them to earn higher wages.</u>

<u></u>

He believed that machines only make human task easier

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8 0
2 years ago
A gas turbine operates with a regenerator and two stages of reheating and intercooling. Air enters this engine at 14 psia and 60
Rzqust [24]

Answer:

flow(m) = 7.941 lbm/s

Q_in = 90.5184 Btu/lbm

Q_out = 56.01856 Btu/lbm

Explanation:

Given:

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- T_6 = 940 = 1400 R

- Heat ratio for air k = 1.4

- Compression ratio r = 3

- W_net,out = 1000 hp

Find:

mass flow rate of the air

rates of heat addition and rejection

Solution:

- Using ideal gas relation compute T_2, T_4, T_10:

                     T_2 = T_1 * r^(k-1/k)

                     T_2 = T_4 = T_10 = 520*3^(.4/1.4) = 711.744 R

- Using ideal gas relation compute T_7, T_5, T_9:

                     T_7 = T_6 * r^(-k-1/k)

                     T_7 = T_5 = T_9 = 1400*3^(-.4/1.4) = 1022.84 R

- The mass flow rate is obtained by:

                     flow(m) = W_net,out / 2*c_p*(1400-1022.84-711.744+520)

                     flow(m) = 1000*.7068 / 2*0.24*(1400-1022.84-711.744+520)

                     flow(m) = 7.941 lbm/s

- The heat input is as follows:

                     Q_in = c_p*(T_6 - T_5)

                     Q_in = 0.24*(1400 - 1022.84)

                     Q_in = 90.5184 Btu/lbm

- The heat output is as follows:

                     Q_out = c_p*(T_10 - T_1)

                     Q_out = 0.24*(711.744 - 520)

                    Q_out = 56.01856 Btu/lbm

                                           

                     

5 0
2 years ago
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