If youre going 70 miles an hour for 70 miles, how long would it take you to travel those 70 miles

B. If you ranked yourself from 6 – 10, describe why it is important to you to be respectful in sports and in other activities, a

kaheart [24]

Answer:

Respect is having a regard for other people and their lives; it is showing those around us compassion and empathy. Children who show respect will find they are successful in all aspects of life. The sports environment is a great place to grow and establish respect.

3 0

2 years ago

Which of the following best characterizes an electron?

barxatty [35]

A, electrons are negatively charged and do orbit around the nucleons

4 0

3 years ago

Read 2 more answers

A boy pulls a sled of mass 5.0 kg with a rope that makes a 60.0° angle with respect to the horizontal surface of a frozen pond.

Oduvanchick [21]

Answer:

μk = 0.124

Explanation:

Known data

m=5.0 kg : mass of the sled

T= 10 N : force with which the boy pulls the rope

θ =60.0° :angle of the rope with respect to the horizontal direction

g = 9.8 m/s² : acceleration due to gravity

Newton's second law to the sled :

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration (m/s²)

Forces acting on the sled

W: Weight of the sled : In vertical and downward direction

N : Normal force : In vertical and upwards direction

f : Friction force: parallel to the movement of the sled and in the opposite direction to the movement

T:Rope tension : forming angle 60.0° of of the rope with respect to the horizontal direction

Calculated of the W of the sled

W= m*g

W= 5.0 kg* 9.8 m/s² = 49 N

x-y components of the tension of the rope T

Tx= 10*cos60°= 5 N

Ty= 10*sin60° = 8.66 N

Calculated of the N

We apply the formula (1)

∑Fy = m*ay ay = 0

N+Ty -W = 0

N = 49 N - 8.66 N

N = 40.34 N

Calculated of the f

f = μk* N

f = μk* 40.34 Equation (1)

We apply the formula (1) to calculated f

∑Fx = m*ax the sled moves with constant velocity, then ax=0

∑Fx = 0

Tx-f = 0

5 - f = 0

f = 5N

We replace f in the equation (1)

5 = μk* 40.34

μk = 5 / 40.34

μk = 0.124

5 0

3 years ago

Identical balls oscillate with the same period T on Earth. Ball A is attached to an ideal spring and ball B swings back and fort

viva [34]

Answer:

B. Ball B will take longer to complete one cycle

Explanation:

This is simply because the period of a simple pendulum is affected by acceleration due to gravity, while the period of an ideal spring is not.

This can be clearly deduced by observing the formulas for the various systems.

Formula for period of simple pendulum:

T = 2π × $\sqrt{\frac{L}{g} }$

Formula for period of an oscillating spring:

T= 2π × $\sqrt{\frac{m}{K} }$

The period of the simple pendulum is affected by the length of the string and the acceleration due to gravity as shown above. Thus, it will have a different period as the gravitational acceleration changes on the moon. Thus will be a larger period <em>(slower oscillation) </em>as the gravitational acceleration is smaller in this case

The period of the oscillating spring is only affected by the mass of the load an the spring constant as shown above. Thus, it will have a period similar to the one it had on the earth because the mass of the ball did not change as the setup was taken to the moon.

All these will make the ball on the spring (Ball B) oscillate faster than the ball swinging on the string (Ball A)

6 0

3 years ago

An object has a gravitational potential energy of 24 joules when it rests on a shelf 3 m above the ground. what would be its gra

wariber [46]

The equation for the gravitational potential energy Ep is:

Ep=m*g*h where m is the mass of the body, g=9.81 m/s² and h is the height of the body.

First we need to find the mass of the body:

m=Ep/(g*h)=24/(9.81*3)=0.82 kg

Now lets see what it's gravitational potential energy would be on the height of 1 m.

Ep=0.82*9.81*1 = 8 J

On the height of 1 m the body has a gravitational potential energy of Ep=8 J.

5 0

3 years ago