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Sindrei [870]
3 years ago
14

If youre going 70 miles an hour for 70 miles, how long would it take you to travel those 70 miles

Physics
1 answer:
Anna11 [10]3 years ago
6 0
490 miles in total ur welcome
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With the aid of a string, a gyroscope is accelerated from rest to 32 rad/s in 0.40 s. What is its angular acceleration in rad/s2
Irina-Kira [14]
<h2>Angular acceleration is 80 rad/s² </h2><h2>Number of revolutions undergone is 1.02</h2>

Explanation:

We have equation of motion v = u + at

     Initial angular velocity, u = 0 rad/s

     Final angular velocity, v = 32 rad/s    

     Time, t = 0.40 s

     Substituting

                      v = u + at  

                      32 = 0 + a x 0.40

                      a = 80 rad/s²

     Angular acceleration is 80 rad/s²

  We have equation of motion s = ut + 0.5 at²

        Initial angular velocity, u = 0 rad/s

        Angular acceleration, a = 80 rad/s²

        Time, t = 0.4 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 0 x 0.4 + 0.5 x 80 x 0.4²

                      s = 6.4 rad

      Angular displacement  = 6.4 rad

     \texttt{Number of revolutions = }\frac{6.4}{2\pi}=1.02

Number of revolutions undergone is 1.02

3 0
3 years ago
A 95kg clock initially at rest on a horizontal floor requires a 560N horizontal force to set it in motion. After the clock is in
miv72 [106K]

Complete Question

A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.

Answer:

The value for static friction is \mu_s =  0.60

The value for static friction is \mu_k =  0.70

Explanation:

From the question we are told that

The mass of the clock is m  =  95 \  kg

The first horizontal force is F _s  =  560 \  N

    The second horizontal force is    F _k  =  650  \  N

Generally the static frictional force is equal to the first  horizontal force

So

     F _s  =  m  *  g  *  \mu_s

=>   560  =  95  *  9.8  *  \mu_s

=>    \mu_s =  0.60

Generally the kinetic frictional force is equal to the second horizontal force

So

      F _k  =  m  *  g  *  \mu_k

      650 =  95  *  9.8  *  \mu_k

     \mu_k =  0.70

3 0
3 years ago
What would decrease the resistance of wires carrying an electric current
Murljashka [212]
I believe the answer is A. shorter wires


3 0
3 years ago
Read 2 more answers
What are the evidences of molecular theory of magnetism​
Assoli18 [71]

Answer:

i hope it helps you please mark me as brainliest

Explanation:

Molecular theory of magnetism states, "If molecular magnets align in a row, then the substance exhibits magnetic property. If they are kept haphazardly, they do not exhibit magnetic property." This is the molecular theory of magnetism. If molecular magnets align in a row, then the substance exhibits magnetic property.

7 0
3 years ago
An astronaut has a mass of 75 kg and is floating in space 500 m from his 125,000 kg spacecraft. What will be the force of gravit
nikdorinn [45]

Answer:

1. 2.5×10¯⁹ N

2. 3.33×10¯¹¹ m/s²

Explanation:

1. Determination of the force of attraction.

Mass of astronaut (M₁) = 75 Kg

Mass of spacecraft (M₂) = 125000 Kg

Distance apart (r) = 500 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force of attraction (F) =?

The force of attraction between the astronaut and his spacecraft can be obtained as follow:

F = GM₁M₂ /r²

F = 6.67×10¯¹¹ × 75 × 125000 / 500²

F = 2.5×10¯⁹ N

Thus, the force of attraction between the astronaut and his spacecraft is 2.5×10¯⁹ N

2. Determination of the acceleration of the astronaut.

Mass of astronaut (m) = 75 Kg

Force (F) = 2.5×10¯⁹ N

Acceleration (a) of astronaut =?

The acceleration of the astronaut can be obtained as follow:

F = ma

2.5×10¯⁹ N = 75 × a

Divide both side by 75

a = 2.5×10¯⁹ / 75

a = 3.33×10¯¹¹ m/s²

Thus, the acceleration the astronaut is 3.33×10¯¹¹ m/s²

5 0
3 years ago
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