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AlladinOne [14]
3 years ago
13

How fast can a human go before they reach terminal velocity?​

Physics
1 answer:
Ne4ueva [31]3 years ago
4 0
Well a terminal velocity is a constant speed, so do u have an equation or number
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Tcecarenko [31]
The answer of this question is B.
5 0
3 years ago
What is a rubens tube
Free_Kalibri [48]

Answer:

its an antique physics apparatus for demonstrating acoustic standing waves in a tube.

6 0
3 years ago
What travels with a sound wave matter, energy or both?
il63 [147K]
Energy travels with sound waves.
8 0
3 years ago
Read 2 more answers
A high school physics student is sitting in a seat read-
Nataly_w [17]

The equilibrium condition allows finding the result for the force that the chair exerts on the student is:

  • The reaction force that the chair exerts on the student's support is equal to the student's weight.

Newton's second law gives the relationship between force, mass and acceleration of bodies, in the special case that the acceleration is is zero equilibrium condition.

            ∑ F = 0

Where F is the external force.

The free body diagram is a diagram of the forces on bodies without the details of the shape of the body, in the attached we can see a diagram of the forces.

Let's analyze the force on the chair.

            N_{chair} - W_{chair} - W_{student} = 0 \\ \\N_{chair} = W_{chair} + W_{student}

Let's analyze the forces on the student.

          N_{student} - W_{student} = 0  \\N_{student} = W _{student}

           

In conclusion using the equilibrium condition we can find the result for the force that the chair exerts on the student is:

  • The reaction force that the chair exerts on the student's support is equal to the student's weight.

Learn more here: brainly.com/question/18117041

7 0
2 years ago
A car drives off a cliff next to a river at a speed of 30 m/s and lands on the bank on theother side. The road above the cliff i
dezoksy [38]

Answer:1.301 s

Explanation:

Given

Initial Velocity(u)=30 m/s

Height of cliff=8.3 m

Time taken to cover 8.3 m

h=ut+\frac{at^2}{2}

here Initial vertical velocity is 0

8.3=\frac{gt^2}{2}

t^2=1.69

t=1.301 s

Horizontal distance

R=u\times t

R=30\times 1.301=39.04 m

7 0
3 years ago
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