D.
All follow an elliptical path that has two foci, rather than a circular path.
Kepler found paths are elliptical, not circular
Their relative speed is the sum of 60 and 40 or 100km/hr. They will travel the 150km in 1.5 hrs.<span>When two object approach each other, the closing speed is just the sum of the speeds, therefore, the closing speed is your case is 100kph. </span>
<span>Just take the distance of 150 km and divide by 100 to get 1.5 hours </span>
<span>checking: </span>
<span>the car going 60 will have traveled 60*1.5 = 90 km </span>
<span>the car going 40 will have traveled 40*1.5 = 60 km </span>
<span>the sum of the distances = 90+60 = 1.5 hours </span>
<span>So they will meet in 1.5 hours.</span>
Answer:
7.78 * 10³ m/s
Explanation:
Orbital velocity is given as:
v = √(GM/R)
G = 6.67 * 10^(-11) Nm/kg²
M = 5.98 * 10^(24) kg
R = radius of earth + distance of the satellite from the surface of the earth
R = 2.15 * 10^(5) + 6.38 * 10^(6)
R = 6.595 * 10^(6) m
v = √([6.67 * 10^(-11) * 5.98 * 10^(24)] / 6.595 * 10^(6))
v = √(6.048 * 10^7)
v = 7.78 * 10³ m/s
Answer:
The velocity of the wave is 12.5 m/s
Explanation:
The given parameters are;
he frequency of the tuning fork, f = 250 Hz
The distance between successive crests of the wave formed, λ = 5 cm = 0.05 m
The velocity of a wave, v = f × λ
Where;
f = The frequency of the wave
λ = The wavelength of the wave - The distance between crests =
Substituting the known values gives;
v = 250 Hz × 0.05 m = 12.5 m/s
The velocity of the wave, v = 12.5 m/s.
Answer:
4.53482 m/s
4.506 m/s
Explanation:
= Mass of player = 75 kg
= Initial velocity of player = 4.6 m/s
= Mass of ball = 0.47 kg
= Initial velocity of ball = 15 m/s
The linear momentum of the system is conserved
The player's speed is 4.53482 m/s
In the second case the equation of momentum is
The player's speed is 4.506 m/s
