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Mariulka [41]
3 years ago
7

Suppose a ray of light traveling in a material with an index of refraction na reaches an interface with a material having an ind

ex of refraction nb. Which of the following statements must be true for total internal reflection to occur?Check all that apply.a. The angle of incidence must be less than the critical angle.b. na = nbc. na > nbd. The angle of incidence must be greater than the critical angle.e. The angle of incidence must be equal to the critical angle.
Physics
1 answer:
ivolga24 [154]3 years ago
5 0

Answer: Option (b) is the correct answer.

Explanation:

It is known that when a ray of light tends to travel from a denser to rarer medium then there occurs total internal reflection.

For a denser medium the refractive index is greater than that of a rarer medium. This means that for the given situation refractive index of medium n_{a} is greater than medium n_{b}.

this also means that incident angle must be greater than the critical angle of the medium.

Thus, we can conclude that the statement n_{a} > n_{b} must be true for total internal reflection to occur.

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astraxan [27]

The angular momentum is m v b where b is known as the impact parameter.

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Does the particle possess any angular momentum about the origin?

The angular momentum is m v b, where b is known as the impact parameter.

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brainly.com/question/3187640

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7 0
2 years ago
What happens to the effort force as the radius increases?
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4 0
3 years ago
What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1
Free_Kalibri [48]

Answer:

Explanation:

just use the gravational force equation which is G x m of earth x m of object divided by r squared (which is radius of earth)

7 0
3 years ago
A rocket is launched at an angle of 39◦ above the horizontal with an initial speed of 90 m/s. It moves for 7 s along its initial
vagabundo [1.1K]

Answer:

Y=1370.23m

Explanation:

The motion have two moments the first one the time the initial velocity is accelerating then when the engines proceeds to move as a projectile

a=19 \frac{m}{s^{2} } \\voy=vo*sin(\alpha )\\voy=90*sin(39 )\\y_{o}=0m\\y_{f}=y_{o}+v_{oy}*t+\frac{1}{2}*a*t^{2}\\y_{f}=90*sin(39)*7s+\frac{1}{2}*19\frac{m}{s^{2} }*(7)^{2}\\y_{f}=861.97m

Now the motion the rocket moves as a projectile so:

v_{fy}=v_{iy}+a*t\\v_{fy}=90+9.8*7\\v_{fy}=158.6 sin(39)

Now the final velocity is the initial in the second one

v_{fy}^{2}=v_{fi}^{2}+2*a*yf \\\\a=g\\

The maximum altitude Vf=0

0=v_{fi}^{2}+2*a*yf \\\\yf=\frac{(158.6 sin(39))^{2} }{2*9.8\frac{m}{s^{2} } } \\yf=508.26m

So total altitude is both altitude of the motion so:

Y=508.2m+861.97m\\Y=1370.23m

6 0
3 years ago
A barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a va
viktelen [127]

Answer:

(a). 14.4 lbf/in^2.

(b). 27.8 in, AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.

Explanation:

So, from the question above we are given the following parameters which are going to help us in solving this particular Question;

=> The "barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a vacuum at the top of the barometer)"

=> "On a day when the temperature is 70oF, the mercury column height is 28.35 inches (corrected for thermal expansion)."

With these knowledge, let us delve right into the solution;

(a). The barometric pressure = water vapor pressure + acceleration due to gravity (ft/s^2) × water density(slug/ft^3) × {ft/12 in}^3 × [ height of mercury column + specific gravity of mercury × height of water column].

The barometric pressure= 0.363 + {(62.146) ÷ (12^3) × 390.6425}. = 14.4 lbf/in^2.

(b). { (13.55 × length of mercury) + 6.5 } × (62.15÷ 12^3) = 14.4 - 0.603.

Length of mercury = 27.8 in.

AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.

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3 years ago
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