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Schach [20]
3 years ago
15

525 grams of tin(II) fluoride are dissolved in water to create a solution with a total

Chemistry
1 answer:
Kazeer [188]3 years ago
4 0

Answer:

MOLARITY =  0.9554 mol/dm3

Explanation:

525 grams of SnF2 in 3.50 L of wate

To obtain the molarity, calculate the concentration in g/dm3 and then concentration in mol/dm3

Concentration in g/dm3  = 525 g/ 3.50 L

= 525g/ 3.50 dm3

= 150g/dm3 of SnF4

Concnetration in mol/dm3

concentration in mol/dm3 = concentration in g/dm3 / Relative molecular mass of SnF2

RMM of SnF2 = ( 119 + 19*2) = 157 g/mol

= 150g/dm3 / 157g/mol

= 0.9554 mol/dm3 of solution.

The molarity of the solution is therefore 0.9554mol/dm3

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