Answer:
Explanation:
When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.
So:
24.42 % = 24.42 g Ca, 17.07% = 17.07g N, 58.5% = 58.5g O
The next step is to divide each mass by their molar mass to convert your grams to moles.
24.42/40.08 = 0.6092 mol
17.07/14.01 = 1.218 mol
58.85/15.99 = 3.680 mol
Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subcripts) of the empircal formula.
0.6092 mol/0.6092 mol = 1
1.218 mol/0.6092 mol = 2
3.680 mol/0.6092 mol = 6
So the empirical formula is
Answer:
[CH₃OH] to decrease and [CO] to increase.
Explanation:
- Since the energy appears as a product. So, the system is exothermic that releases heat.
- Increasing the temperature of the system will cause the system to be shifted to the left side to attain the equilibrium again.
<em>[CH₃OH] to decrease and [CO] to increase.</em>
<em></em>
B. Fluorine (F) is the right answer
Chemist Fritz Haber and engineer Carl Bosch discovered a way to make ammonia efficiently.
They actually discovered a process that is Haber-Bosch process that is a process of nitrogen fixation that provides manufacturing of ammonia industially. Haber-Bosch process is an artificial process of nitrogen fixation. That is a process of manufacturing ammonia industially.
Answer:
copper will reach to higher temperature first.
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
The substances with higher value of specific heat capacity require more heat to raise the temperature by one degree as compared the substances having low value of specific heat capacity.For example,
The specific heat capacity of copper is 0.386 j/g. K and for aluminium is 0.900 j/g.K. So, aluminium take a time to increase its temperature by one degree by absorbing more heat while copper will heat up faster by absorbing less amount of heat.
Consider that both copper and aluminium have same mass of 5g and change in temperature is 15 K. Thus amount of heat thy absorbed to raise the temperature is,
For copper:
Q = m.c. ΔT
Q = 5 g× 0.386 j/g K × 15 K
Q = 28.95 j
For aluminium:
Q = m.c. ΔT
Q = 5 g× 0.900 j/g K × 15 K
Q = 67.5 j
we can observe that aluminium require more heat which is 67.5 j to increase its temperature. So it will reach to higher temperature later as compared to copper.
