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Nezavi [6.7K]
3 years ago
13

There are many different types of models. Look at the three models. How are the models alike? How are they different?

Chemistry
2 answers:
cluponka [151]3 years ago
7 0

Answer:

Models 2 and 3 mind giving me branliest again?

Explanation:

charle [14.2K]3 years ago
5 0

Answer:

Models 2 and 3

Explanation:

Just makes sense. Hope this helps.

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Write a complete step-by-step plan for dealing with broken glassware on the floor or lab table. Write your plan in list form in
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1 tell the person in charge or the teacher
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What is the maximum number of grams of PH3 that can be formed when 6.2 g of phosphorus reacts with 4.0 g of hydrogen to form PH3
kvv77 [185]

Answer:

6.79 g of phosphine can be produced

Explanation:

The reaction is this:

3H₂ + 2P → 2PH₃

We have the mass of the two reactants, so let's find out the limiting reactant, so we can work with the equation. Firstly, we convert the mass to moles (mass / molar mass)

6.2 g / 30.97 g/mol = 0.200 moles of P

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Ratio is 3:2.

3 moles of hydrogen react with 2 moles of P

Then, 2 moles of H₂ would react with (2 . 2)/ 3 = 1.3 moles of P.

We have only 0.2 moles of P, so clearly the phosphorous is the limiting reactant.

Ratio is 2:2. So 2 moles of P can produce 2 moles of phosphine. Therefore, 0.2 moles of P must produce the same amount of phosphine.

Let's convert the moles to mass ( mol . molar mass)

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3 0
3 years ago
God, cure my stupidity.
Cloud [144]
The answer is the third one
4 0
3 years ago
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Which of the following is a physical property of a substance?
vaieri [72.5K]
B boiling point https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Map%3A_Introductory_Chemistry_(Tro)/03%3A_Matter_and_Energy/3.05%3A_Differences_in_Matter%3A_Physical_and_Chemical_Properties#Summary
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What is the molarity of a solution that contains 17g of NH₃ in 0.50L of solution?
erastovalidia [21]

Explanation:

Because molarity is mol/L, we'll have to convert 17g to mol.

After obtaining the mol, we'll divide that by the volume to obtain Molarity.

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3 years ago
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