Answer:
ΔH = 57.04 Kj/mole H₂O
Explanation:
60ml(0.300M Ba(OH)₂(aq) + 60ml(0.600M HCl(aq)
=> 0.06(0.3)mole Ba(OH)₂(aq) + 0.60(0.6)mole HCl(aq)
=> 0.018mole Ba(OH)₂(aq) + 0.036mole HCl(aq)
=> 100% conversion of reactants => 0.018mole BaCl₂(aq) + 0.036mole H₂O(l) + Heat
ΔH = mcΔT/moles H₂O <==> Heat Transfer / mole H₂O
=(120g)(4.0184j/g°C)(27.74°C - 23.65°C)/(0.036mole H₂O)
ΔH = 57,042 j/mole H₂O = 57.04 Kj/mole H₂O
It B I just took the test ;)
Answer:
Explanation:
[ so₃] = 4.37 x 10⁻²
[so₂] = 4.77 x 10⁻²
[ o₂] = 4.55 x 10⁻²
Qc = (4.37)²x10⁻⁴ /(4.77)².(4.55) x 10⁻⁶ =18.44
Qc is less than Kc hence in order to reach equilibrium more of so₃ will be produced . Statement 1 is true.
Kc is always constant . Statement 2 is false.
Statement 3 is false because statement 1 is true.
Qc Is smaller than Kc . So statement 4 is false.
The reaction is not in equilibrium. Statement 5 is false.
The standard of something as measured against other things of a similar kind; the degree of excellence of something
