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Anettt [7]
4 years ago
10

It is NOT possible for a virus to infect a bacterium. T or F

Chemistry
1 answer:
Schach [20]4 years ago
8 0

Answer: F

Explanation:

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According to the chemical formula shown below, all of the following elements are found in phosphoric acid EXCEPT
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The mountain peaks shown below were initially formed millions of years ago through the processes of folding, faulting, and overt
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Answer:

A. Erosion  

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Erosion is the process in which soil and rock are worn away and transported by wind or water and transported to another location.

The image below shows how water has eroded a coastline.

B is wrong. Chemical weathering is the disintegration of rocks by reactions with water and the acids dissolved in it

C is wrong. Deposition is the process in which sediments carried by wind, water or ice are deposited at another location.

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Draw the structure of the compound C9H10O2 that might exhibit the 13C-NMR spectrum below. Impurity peaks are omitted from the pe
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Complete question

Draw the structure of the compound C_{9}H_{10}O_{2} that exhibits the ^{13}C-NMR spectrum shown on the first uploaded image(on the second and third uploaded image is closer look at the ^{13}C-NMR spectrum ) . Impurity peaks are omitted from the peak list. The triplet at 77 ppm is CDC_{l3}.

Answer:

The structure that might exhibit the ^{13}C-NMR  spectrum is shown on the fifth uploaded image

Explanation:

    In order to get a good understanding of the answer above we need to know that

• Proton NMR spectrum: proton NMR spectroscopy is one of the techniques, which is useful to predict the structure of the compound.

• In ^{\rm{1}}{\rm{H NMR}}  spectroscopy, peaks are observed at the point where the wavelength of proton nuclei matched to substance nuclei wavelength.

• In same manner there are other spectroscopies are present like ^{{\rm{13}}}{\rm{C NMR}}

, IR and mass spectroscopy.

• Infrared spectroscopy is used to determine the functional groups present in a compound.

• Infrared bands observed when there is change in dipole moment occurs between the atoms. Infrared bands describe about the bond stretches, which causes due to the dipole moment present in the molecule.

Fundamentals

Double bond equivalence: number of double bonds or number of rings in the structure can be calculated by using double bond equivalence formula.

DBE = N_{c} + 1 - (\frac{N_{H}+N_{Cl}-N_{N}}{2}})

Where,

N_{c} = number of carbon atoms

N_{H}= number of hydrogen atoms

N_{Cl} = number of chlorine atoms

N_{N}=number of nitrogen atoms

The table for the ^{{\rm{13}}}{\rm{C NMR}} is shown on the fourth uploaded image

Molecular formula of the compound is {{\rm{C}}_9}{{\rm{H}}_{{\rm{10}}}}{{\rm{O}}_{\rm{2}}}

Double bond equivalence of the compound is calculated below.

  DBE = N_{c} + 1 - (\frac{N_{H}+N_{Cl}-N_{N}}{2}})

Where,

N_{c} = 9

N_{H}= 10

N_{Cl} = 0

N_{N}= 0

                    DBE = N_{c} + 1 - (\frac{(10+0) -0}{2}})

                    DBE =5

Therefore, the compound has five double bonds, which indicating that there is chance of getting aromatic rings too.

Note:

Double bond equivalence is calculated as 5 which indicates that there are 5 double bond (may rings) in the structure of the compound.

Double bond equivalence is calculated by using this formula.

           DBE = N_{c} + 1 - (\frac{N_{H}+N_{Cl}-N_{N}}{2}})

13C NMR data of the compound is explained below.

1.A peak at 166.5 ppm, which indicates the presence of ester group

2.Peaks at 132.7, 130.5, 129.5, 128.2 ppm (aromatic carbons) are indicating a mono substituted aromatic ring

3.A peak at 60.9 ppm means methylene group attached to oxygen atom

4.A peak at 14.3 ppm, which indicates the presence of methyl group

According to this data and the using the double bond equivalence, structure of the compound shown on the fifth uploaded image .

Note:

According to given spectral data, structure of the compound has been predicted. It is clear that; -ester functional group is present in the structure because there is a peak at 166.5ppm. According to given proton ^{13}C NMR data, above structure has been drawn. Therefore, the compound is ethyl benzoate.

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