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3 years ago

10

Major league baseball's fastest recorded pitch is 105 miles per hours. The distance between the pitcher's mound and home plate i

s 60 feet, 6 inches. How long did it take the ball to travel from the pitcher to the batter?

1 answer:

blsea [12.9K]3 years ago

6 0

Answer:

0.4 sec

Step-by-step explanation:

Remember that

1 mile=5,280 feet

1 foot=12 inches

1 hour=3,600 seconds

Let

s -----> the speed in ft/sec

d ----> the distance in ft

t -----> the time in sec

s=d/t

Solve for t

t=d/s

step 1

Convert miles/hour to ft/sec

105 mi/h=105(5,280/3,600)=154 ft/sec

Convert 60 ft 6 in to ft

60 ft 6 in=60+(6/12)=60.5 ft

step 2

Find the time

t=d/s

we have

s=154 ft/sec

d=60.5 ft

substitute

t=60.5/154

t=0.39 sec

Round to the nearest tenth

t=0.4 sec

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Answer: 31 & 42

<u>Step-by-step explanation:</u>

1st #: x

2nd #: x + 11

1st# + 2nd# = sum

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2x = 62

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genetic experiment with peas resulted in one sample of offspring that consisted of green peas and yellow peas. a. Construct a %

Andreas93 [3]

Complete Question

A genetic experiment with peas resulted in one sample of offspring that consisted of 432 green peas and 164 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?

Answer:

The 95% confidence interval is $0.2392 < p < 0.3108$

No, the confidence interval includes 0.25, so the true percentage could easily equal 25%

Step-by-step explanation:

From the question we are told that

The total sample size is $n = 432 + 164 =596$

The number of offspring that is yellow peas is $y = 432$

The number of offspring that is green peas is $g = 164$

The sample proportion for offspring that are yellow peas is mathematically evaluated as

$\r p = \frac{ 164 }{596}$

$\r p = 0.275$

Given the the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = (100 - 95)\%$

$\alpha = 5\% = 0.0 5$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r p (1- \r p )}{n} }$

=> $E = 1.96 * \sqrt{\frac{0.275 (1- 0.275 )}{596} }$

=> $E = 0.0358$

The 95% confidence interval is mathematically represented as

$\r p - E < p < \r p + E$

=> $0.275 - 0.0358 < p < 0.275 + 0.0358$

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horsena [70]

Answer:74.55 beat per minute

Step-by-step explanation:

Given

Heart beat is 52 beat per minute

i.e. $B=\frac{52}{60}$ beat per sec

If heart rate is increases 1.25 % each sec

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$B_2=B(1+1.25 \% )$

For 3 rd sec

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$B_3=B(1+1.25\%)^2$

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