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Answer: It stays the same
Explanation:
Answer:
V = 12.93 L
Explanation:
Given data:
Number of moles = 0.785 mol
Pressure of balloon = 1.5 atm
Temperature = 301 K
Volume of balloon = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will put the values.
V = nRT/P
V = 0.785 mol × 0.0821 atm.L/ mol.K × 301 K / 1.5 atm
V = 19.4 L /1.5
V = 12.93 L
Answer:
1/2 ( the two answers given are not FRACTIONS)
Explanation:
Moles of CH3OH = 128 gm / 32 gm / mole = 4 moles
Moles of water 72 gm / 18 gm /mole = 4
Mole fraction of CH3OH = 4 / ( 4+4) = 4/8 = 1/2
Answer : The volume (in mL) of 95% ethanol added would be, 1.39
Explanation :
As we are given that:
Mass of 95 % ethanol = 1.2 g
Density of 95 % ethanol = 0.86 g/mL
Formula used :
Therefore, the volume (in mL) of 95% ethanol added would be, 1.39
