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8090 [49]
2 years ago
8

Which of the following statements is true? a. Ag(s) reacts spontaneously with 1 M H+(aq). b. Ag(s) reacts spontaneously with Ni2

+. c. Ag(s) reacts spontaneously with 1 M NO3– in 1 M H+(aq). d. Ni2+ reacts spontaneously with 1 M H+(aq) to form H2. e. Ni2+ reacts spontaneously with H2(g).
Chemistry
1 answer:
sammy [17]2 years ago
5 0

Answer:

Correct answer is a. Ag(s) reacts spontaneously with 1M H+(aq).

Explanation:

A charasteristic of metals is that they lose easily electrons, cations tends to gain electrons to react and anions tends to lose or share electrons to react.

If you want to make a chemical reaction you must to mix a reagent that tends to lose electrons with other that tends to gain them.

In the statement (a) we have a metal that loses electrons and a cation that can obtain them, so is the right answer.

note that the other optios have :

b) Metal with metal cation, not react beacause left a medium of reaction.

c) Both loses electrons

d) Both tends to gain electrons.

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What must happen for an igneous rock to form
Ksenya-84 [330]

Answer:

Igneous Rocks: form by crystallizing melted material (magma).

Explanation:

They can form either on the surface (extrusive igneous rocks), or deep in the crust (intrusive or plutonic igneous rocks).

4 0
2 years ago
A student is given the question: "what is the mass of a gold bar that is 7.379 × 10–4 m3 in volume? the density of gold is 19.3
IRINA_888 [86]

<em>The mass of a gold bar  = 1.424 x 10⁴ gram</em>

<em></em>

<h3><em>Further Explanation</em></h3>

Density is a quantity derived from the mass and volume

density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than type

The unit of density can be expressed in g / cm3 or kg / m3

Density formula:

\large{\boxed{{\bold{\rho~=~\frac{m}{V}}}}

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm3

The mass itself is often equated with weight, even though it is different. Mass is the amount of matter in the matter while weight is related to the gravitational force

<em>Known variable</em>

volume gold bar 7.379 × 10⁻⁴ m³

a density of 19.3 g/cm³

<em>Asked</em>

the mass of a gold bar

<em>Answer</em>

volume is known to be 7.379 × 10⁻⁴ m³, then we change it first to units of cm³ adjusting to units of density

7.379 × 10⁻⁴ m³ = 7.379 × 10² cm³

then:

mass = volume x density

mass = 7.379 × 10² cm³ x 19.3 g/cm³

mass = 1.424 x 10⁴ gram

<h3><em>Learn more </em></h3>

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Keywords: density, mass, volume, a gold bar

3 0
3 years ago
Read 2 more answers
Calculate the maximum volume in ml of 0.15M HCl that each of the following antacid formulations would be expected to neutralize.
vlada-n [284]

a. 34 mL; b. 110 mL

a. A tablet containing 150 Mg(OH)₂


Mg(OH)₂ + 2HCl ⟶ MgCl₂ + 2H₂O


<em>Moles of Mg(OH)₂</em> = 150 mg Mg(OH)₂ × [1 mmol Mg(OH)₂/58.32 mg Mg(OH)₂

= 2.572 mmol Mg(OH)₂


<em>Moles of HCl</em> = 2.572 mmol Mg(OH)₂ × [2 mmol HCl/1 mmol Mg(OH)₂]

= 5.144 mmol HCl


Volume of HCl = 5.144 mmol HCl × (1 mmol HCl/0.15 mmol HCl) = 34 mL HCl


b. A tablet containing 850 mg CaCO₃


CaCO₃ + 2HCl ⟶ CaCl₂ + CO₂ + H₂O


<em>Moles of CaCO₃</em> = 850 mg CaCO₃ × [1 mmol CaCO₃/100.09 mg CaCO₃

= 8.492 mmol CaCO₃


<em>Moles of HCl</em> = 8.492 mmol CaCO₃ × [2 mmol HCl/1 mmol CaCO₃]

= 16.98 mmol HCl


Volume of HCl = 16.98 mmol HCl × (1 mL HCl/0.15 mmol HCl) = 110 mL HCl


5 0
2 years ago
A photon of light has an energy of 1.83 x 10-18). What is the wavelength of this light? Does this light fall in the IR, visible,
Scrat [10]

Answer:

1.09 × 10⁻⁷ m

UV region

Explanation:

Step 1: Given and required data

Energy of the photon of light (E): 1.83 × 10⁻¹⁸ J

Planck's constant (h): 6.63 × 10⁻³⁴ J.s

Speed of light (c): 3.00 × 10⁸ m/s

Step 2: Calculate the wavelength (λ) of this photon of light

We will use the Planck-Einstein's relation.

E = h × c/λ

λ = h × c/E

λ = 6.63 × 10⁻³⁴ J.s × (3.00 × 10⁸ m/s)/1.83 × 10⁻¹⁸ J = 1.09 × 10⁻⁷ m

This wavelenght falls in the UV region of the electromagnetic spectrum.

4 0
2 years ago
using the equation, C5H12 + 8O2 -&gt; 5CO2 + 6H2O, if 108 g of water are produced, how many grams of oxygen were consumed?
vodomira [7]
Molar mass:

H₂O = 18.0 g/mol

O₂ = 32.0 g/mol

<span>C</span>₅<span>H</span>₁₂<span> + 8 O</span>₂<span> -> 5 CO</span>₂<span> + 6 H</span>₂<span>O
</span>
8 x (32 g ) ------------ 6 x (18 g )
mass O₂ ------------ 108 g H₂O

mass O₂ = 108 x 8 x 32 / 6 x 18

mass O₂ = 27648 / 108

mass O₂ = 256 g

hope this helps!

3 0
3 years ago
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