Answer:
Final molarity of iodide ion C(I-) = 0.0143M
Explanation:
n = (m(FeI(2)))/(M(FeI(2))
Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol
So n = 0.981/309.85 = 0.0031 mol
V(solution) = 150mL = 0.15L
C(AgNO3) = 35mM = 0.035M = 0.035m/L
n(AgNO3) = C(AgNO3) x V(solution)
= 0.035 x 0.15 = 0.00525 mol
(AgNO3) + FeI(3) = AgI(3) + FeNO3
So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol
C(I-) = C(FeI(3)) = [n(FeI(3)) excess]/ [V(solution)] = 0.00215/0.15 = 0.0143mol/L or 0.0143M
Answer:
<u>2-chlorohexane</u>
Explanation:
<u>In this figure</u> :
- There are 6 carbon atoms
- The Cl atom is bonded to the 2nd carbon atom
⇒ The Cl is a substituent group, termed as -chloro
⇒ Based on IUPAC nomenclature, the 6 atom chain starts with hex
⇒ There are only single bonds present, so it is an alkane
<u>The name is</u> :
Answer:
Explanation:
A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products . A product is a substance that is present at the end of a chemical reaction.
h2 + 02 = h2o
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