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sp2606 [1]
3 years ago
7

Jupiter, Saturn, Uranus, and Neptune: what is one reason why life probably does not exist on these four planets? A) They have no

gravity. B) They are the gas planets. C) They are the giant planets. D) They are the rocky planets.
Chemistry
1 answer:
mariarad [96]3 years ago
7 0

Answer: B.) They are all gas planets

I hope this helps!

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Which process occurs in all living organisms at all times?
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Cellular respiration <span />
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Tetrachloromethane,CC15,is classified as a
prohojiy [21]
Correct Answer: compound because the atoms of the elements are combined in a fixed proportion.
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4 years ago
How many ions are in sodium bicarbonate
djyliett [7]

Answer:

Sodium bicarbonate molecules feature one sodium cation and one bicarbonate anion. Here, an ionic bond is formed between the positively charged sodium ion and the negatively charged oxygen (which is singly bonded to the central carbon and not bonded to a hydrogen atom).

Explanation:

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3 years ago
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If u mix 10ml of 70%ethanol with 20ml of 80% ethanol with 50ml water what is the concentration of the resulted solution
morpeh [17]

Answer:

29% is the final concentration

Explanation:

To solve this question we must find the volume of ethanol added and the volume of the whole solution. The concentration will be:

Volume ethanol / Total volume * 100

<em>Volume ethanol:</em>

10mL * 70% = 7mL ethanol

+

20mL * 80% = 16mL ethanol

= 23mL ethanol

<em>Total volume:</em>

10mL + 20mL + 50mL = 80mL

<em>Concentration:</em>

23mL / 80mL * 100

= 29% is the final concentration

6 0
3 years ago
A 1.40 L sample of O2 at 645 Torr and 25 °C, and a 0.751 L sample of N2 at 1.13 atm and 25 °C, are both transferred to the same
anyanavicka [17]

Answer:

  • P(O₂) = 0.595 atm
  • P(N₂) = 0.424 atm
  • Total Pressure = 1.019 atm

Explanation:

To solve this problem we use PV=nRT for both gases in their containers, in order to <u>calculate the moles of each one</u>:

  • O₂:

645 Torr ⇒ 645 /760 = 0.85 atm

25°C ⇒ 25 + 273.16 = 298.16 K

0.85 atm * 1.40 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K

n = 0.0487 mol O₂

  • N₂:

1.13 atm * 0.751 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K

n = 0.0347 mol N₂

Now we can <u>calculate the partial pressure for each gas in the new container</u>, because the number of moles did not change:

  • O₂:

P(O₂) * 2.00 L = 0.0487 mol O₂ * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K

P(O₂) = 0.595 atm

  • N₂:

P(N₂) * 2.00 L = 0.0347 mol N₂ * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K

P(N₂) = 0.424 atm

Finally we add the partial pressures of all gases to <u>calculate the total pressure</u>:

  • Pt = 0.595 atm+ 0.424 atm = 1.019 atm
6 0
3 years ago
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