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Sphinxa [80]
3 years ago
9

In Humans, the liquid waste

Chemistry
1 answer:
Kay [80]3 years ago
8 0
The answer is b (bladder)
You might be interested in
Solid carbon (C) can burn in oxygen (O2). Select
babunello [35]

Answer:

OCO

Another way of writing CO₂

Explanation:

A reaction equation has <u>reactants on the left</u> and <u>products on the right</u>.

The reactants are carbon and oxygen. The product is carbon dioxide.

C + O₂ → CO₂

You might see the equation both ways.

C + O₂ → OCO

C + O₂ in the products would mean no reaction has occurred. The problem can <u>solid carbon can burn in oxygen</u>, so a reaction will occur. For no reaction, you would put "NR" in the products.

<u>OCO is the structural way of writing CO₂.</u> Both have one carbon atom (C) and two oxygen atoms (O).

C + 2O is not possible. Oxygen, if alone, has to be at least O₂ because it's a <u>diatomic molecule</u>.

3 0
3 years ago
Which of the following is an element?
Kryger [21]

Oxygen is a chemical element with symbol O and atomic number 8. Classified as a nonmetal, Oxygen is a gas at room temperature.

8 0
3 years ago
Would the N=O bond in HNO2 be longer, shorter, or the same length as the N-O bonds in NO2-?
aivan3 [116]

Explanation:

Bond order is inversely proportional to the bond length.

B.O\propto \frac{1}{B.L}

In HNO_2 molecule. one nitrogen is double bonded to nitrogen and one oxygen is single bonded to nitrogen and hydrogen bond.

  • Bond order between the (N=O) bond is 2 which means that bond length between the (N=O) bond is shorter than that of the N-O bond.
  • Bond order between the (N-O) bond is 1 which means that bond length of the N-O bond is longer than that of the bond length of (N=O) bond.
3 0
3 years ago
Read 2 more answers
50 points plz help
EleoNora [17]

Answer: b

Explanation:

7 0
3 years ago
How many grams of Na2So4 would be formed if 0.75 moles of NaOH reacted?
Nata [24]

Answer:

\boxed{\text{53 g }}

Explanation:

You don't give the reaction, but we can get by just by balancing atoms of Na.

We know we will need the partially balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r:                                 142.04  

             2NaOH + … ⟶ Na₂SO₄ + …  

n/mol:      0.75

1. Use the molar ratio of Na₂SO₄ to NaOH to calculate the moles of NaF.

Moles of Na₂SO₄ = 0.75 mol NaOH × (1 mol Na₂SO₄/2 mol NaOH

= 0.375 mol Na₂SO₄

2. Use the molar mass of Na₂SO₄ to calculate the mass of Na₂SO₄.

Mass of Na₂SO₄ = 0.375 mol Na₂SO₄ × (142.04 g Na₂SO₄/1 mol Na₂SO₄) = 53 g Na₂SO₄

The reaction produces \boxed{\text{53 g }} of Na₂SO₄.

4 0
3 years ago
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