Answer:
We learned that an ideal multiple access protocol has FOUR desirable
characteristics, describe them.
Explanation:
1.- Very experienced technology and easy to implement.
2.- Rigid resource management and unfit for variable traffic flows.
3.- Requires antenna duplexer for duplex transmission.
<u>Duplex</u> <em>is a term used in telecommunication to define a system that is capable of maintaining two-way communication, sending and receiving messages simultaneously.
</em>
4.- Normally FDMA is combined with multiplexing FDD.
<u>FDMA</u> (acronym in English for Frequency Division Multiple Access) <em>is a multiplexing technique used in multiple communication protocols, both digital and analog, mainly radio frequency, and among them in mobile phones of GSM networks.
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<u>FDD</u> (Frequency Division Duplexing in English) <em>designates a duplex method in the environment of wireless telecommunications and over certain wired networks.</em>
Answer:
Incomes
Explanation:
Project management has to do with the process of achieving a set goal with the help of a team within a specified time. Most times, the main problem that comes with project management is completing the project within the available constraints.
No project can start up without funds, which in this case is called income and this is the part of the project that determines the overall work.
The simulation, player 2 will always play according to the same strategy.
Method getPlayer2Move below is completed by assigning the correct value to result to be returned.
Explanation:
- You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.
#include <bits/stdc++.h>
using namespace std;
bool getplayer2move(int x, int y, int n)
{
int dp[n + 1];
dp[0] = false;
dp[1] = true;
for (int i = 2; i <= n; i++) {
if (i - 1 >= 0 and !dp[i - 1])
dp[i] = true;
else if (i - x >= 0 and !dp[i - x])
dp[i] = true;
else if (i - y >= 0 and !dp[i - y])
dp[i] = true;
else
dp[i] = false;
}
return dp[n];
}
int main()
{
int x = 3, y = 4, n = 5;
if (findWinner(x, y, n))
cout << 'A';
else
cout << 'B';
return 0;
}
Answer:
Keeping as few emoji's as possible. This helps because lots of emoji's can make things confusing and/or annoying. This just means being kind to the person you're messaging and not making things confusing.
