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3 years ago

What determines the frequency of an electromagnetic wave

Physics

1 answer:

Ostrovityanka [42]3 years ago

5 0

<h2>The frequency depends upon the source energy of electromagnetic waves</h2>

Explanation:

The energy of electromagnetic wave is

E = h ν

E is the energy of source emitting the waves

here h is Plank's constant

and ν is used for the frequency of the electromagnetic wave

Thus the frequency of wave depends upon the energy of electromagnetic source . Because h is constant .

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Solnce55 [7]

Answer:

Yes

Explanation:

The spring force is given as:

F = kd

F is the spring force

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d is the magnitude of the stretch

Since k is a constant, therefore, doubling the stretch distance will double the force.

Both stretch distance and force applied can be said to be directly proportional to one another.

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kolbaska11 [484]

Answer:

Final volumen first process $V_{2} = 98,44 cm^{3}$

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Explanation:

Using the Ideal Gases Law yoy have for pressure:

$P_{1} = \frac{n_{1} R T_{1} }{V_{1} }$

where:

P is the pressure, in Pa

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T is the temperature in Kelvin

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Given that the amount of material is constant in the process:

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In an isobaric process the pressure is constant so:

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$\frac{T_{1} }{V_{1} } = \frac{T_{2} }{V_{2} }$

$V_{2} = \frac{T_{2} V_{1} }{T_{1} }$

Replacing : $T_{1} =786 K, T_{2} =1209 K, V_{1} = 64 cm^{3}$

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Replacing on the ideal gases formula the pressure at this piont is:

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$T = \frac{P V }{n R }$

For the second process you have that $T_{2} = T_{3}$ So:

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$P_{2} V_{2} = P_{3} V_{3}$

$P_{3} = \frac{P_{2} V_{2}}{V_{3}}$

$P_{3} = 1,317 * 10^{10} Pa$

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3 years ago

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romanna [79]

Answer:

Explanation:

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