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Diano4ka-milaya [45]
3 years ago
14

During the Patient Care Era, a more demanding and educated public now expected the pharmacist to be a therapeutic advisor and __

_____________.
Physics
1 answer:
Murrr4er [49]3 years ago
3 0
Make a lot of money for what they do
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Two 13 cm -long thin glass rods uniformly charged to +11nC are placed side by side, 4.0 cm apart. What are the electric field st
DedPeter [7]

Answer:

E1  = 10.15 * 10^4 N/C

E2 = 0

E3 = 10.15 *10^4 N/C

Explanation:

Given data:

Two 13 cm-long thin glass rods ( L ) = 0.13 m

charge (Q)  = +11nC

distance between thin glass rods   = 4 cm .

<u>Calculate the electric field strengths </u>

electric charge due to a single glass rod in the question ( E ) = \frac{Q}{2\pi e_{0}rL }

equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced

applying equation 1 to determine E1

E1 = \frac{Q}{2\pi e_{0}rL } ( \frac{1}{0.01} - \frac{1}{0.03} )    ( distance from 1 rod is 0.01 m and from the other rod is 0.03 )

   = \frac{11*10^{-9} }{2*3.14*8.85*10^{-12}*0.13 } ( 66.67 )

   = 10.15 * 10^4 N/C

applying equation 1 to determine E2

E2 = \frac{Q}{2\pi e_{0}rL }( \frac{1}{0.02} - \frac{1}{0.02} )

therefore E2 = 0

E1 = E3

hence E3 = 10.15*10^4 N/C

4 0
3 years ago
Visible light represents a very small portion of the electromagnetic spectrum. Radiation to the left in the image, such as micro
amid [387]
X rays have a higher frequency so A
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What is the acceleration of a baseball that has a final velocity of 15.0 m/s when it crosses the plate 2.0 seconds after leaving
Leokris [45]
I think it’s A pretty sure...
3 0
3 years ago
Please help this is physics!!!
larisa [96]
I’m pretty sure u have it right
8 0
3 years ago
A sports car skids off of a wet mountain road at 48.5 m/s and lands in the river, 110
Oxana [17]

Answer:

  about 4.74 seconds

Explanation:

The time to fall distance d from height h is given by ...

  t = √(2d/g)

  t = √(2·110 m/(9.8 m/s^2)) ≈ 4.74 s

It will take the car about 4.74 seconds to fall 110 meters to the river.

__

We assume the car's speed is horizontal, so does not add or subtract anything to/from the time to fall from the height.

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3 years ago
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