Answer:
Workdone = 12.2 Joules
Explanation:
Given:
Force applied on the pencil = 47 N
Displacement of the pencil = 0.26 m
We have to find the work done .
Note:
Workdone = Product of force and its displacement (in the direction of the force) .
So,
Plugging the values.
Workdone =
⇒
⇒
⇒ Joules (J)
OR
We can say that the displacement is against the direction of applied force.
Displacement = - 0.26
Workdone =
⇒ is the angle between force and displacement.
⇒ Here,
⇒
Workdone (W) =
⇒
⇒ Joules (J).
Workdone on pushing the pencil = 12.2 Joules.
The charge on the positive plate is 1.734* C
Given,
V=9v, R=0.066m Gap(G)=2.0mm=0.0020m ∈=8.85*
We know C=∈ * = 8.85* *=19.275* F
Also, Q = C V = 19.275* * 9 = 1.734* C
<h3>Charge </h3>
When charged matter is exposed to an electromagnetic field, its electric charge—a property of matter—causes it to feel a force. A charge on an electric field might be positive or negative. Like and unlike charges are attracted to one another while being repelled by the other. Neutral describes a thing without any net charge. Electric charge is a conserved property; in an isolated system, the net charge, or the sum of the positive and negative charges, is constant. Subatomic particles transport electrical charge. The protons in atoms' nuclei carry positive charge in normal matter, while the electrons carry negative charge.
Learn more about charge here:
brainly.com/question/19886264
#SPJ4
Answer:
How do you find out the missing masses in a balloon?
Well, actually you can't find the missing masses in a balloon. Why?
Because the mass of the mass of balloon, it can't see the mass of it, it only see if it the balloon is deflated or inflated.
Explanation:
Hope it helps
#LetsStudy
1. Frequency:
The frequency of a light wave is given by:
where
is the speed of light
is the wavelength of the wave
In this problem, we have light with wavelength
Substituting into the equation, we find the frequency:
2. Period:
The period of a wave is equal to the reciprocal of the frequency:
The frequency of this light wave is (found in the previous exercise), so the period is:
Answer:
C
Explanation:
Since the circuit is in parallel there will be no effect on the other loads.