Answer:
Option (C) is correct.
Explanation:
Assuming that the hiker starts walking from the origin O as shown in the figure.
First, he walks 200 m west to point A (say), then he walks 100 m north to the final point B (say) as shown in the figure.
The final point B is in the north-west direction, therefore, the resulting point is in the north-west direction.
Hence, option (C) is correct.
"<span>There can only be one voltage supplied" is the statement among the statements given in the question that true regarding DC current. The correct option among all the options that are given in the question is the second option or option "B'. I hope the answer comes to your help.</span>
Answer:
The induced current and the power dissipated through the resistor are 0.5 mA and
.
Explanation:
Given that,
Distance = 1.0 m
Resistance = 3.0 Ω
Speed = 35 m/s
Angle = 53°
Magnetic field 
(a). We need to calculate the induced emf
Using formula of emf

Where, B = magnetic field
l = length
v = velocity
Put the value into the formula


We need to calculate the induced current


Put the value into the formula


(b). We need to calculate the power dissipated through the resistor
Using formula of power

Put the value into the formula


Hence, The induced current and the power dissipated through the resistor are 0.5 mA and
.
First, we must find the vertical distance traveled upwards by the ball due to the throw. For this, we will use the formula:
2as = v² - u²
Because the final velocity v is 0 in such cases
s = -u²/2a; because both u and a are downwards, the negative sign cancels
s = 14.5² / 2*9.81
s = 10.72 meters
Next, to find the time taken to reach the ground, we need the height above the ground. This is:
45 + 10.72 = 55.72 m
We will use the formula
s = ut + 0.5at²
to find the time taken with the initial velocity u = 0.
55.72 = 0.5 * 9.81 * t²
t = 3.37 seconds
Answer:
P = 147,75 W
Explanation:
A man whose mass is 59.1kg climbs up 30 steps of a stair each step is 25 cm high
Height at 30 steps , h=30×2.5= 7.5 m
Change in potential energy , =mgh=59.1×10×7.5 = 4432.5 J
So, Work done by the man , W= 4432.5J
Power used , P= 
P = 4432.5 /30
P = 147,75 W
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