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ICE Princess25 [194]
3 years ago
15

How do you find the length of a circle in geometry?

Mathematics
2 answers:
Mice21 [21]3 years ago
8 0
The length of the circle is the same thing as its circumference
circumference= 2×π×radius²
Andrew [12]3 years ago
6 0
Exactly the same way you find any missing item in any other subject:
You take the information you're given, and you collect everything you know about
relationships between the information you have and the item you have to find.
Finally, you use the relationships and the given information to find the value of the
missing item.

The process you'll use to find the circumference of a circle will depend on what
information you DO have about the circle.
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The midpoint of AB is M(1, 6). If the coordinates of A are (8, 4), what are the coordinates of B?
Ne4ueva [31]

Answer:

(-6,8)

Step-by-step explanation:

8+x2=2       4+y2=12

x2= -6         y2= 8

4 0
3 years ago
Can't quite figure out the limit problem ​
alisha [4.7K]

Use the squeeze theorem; if

1 - <em>x</em> ²/4 ≤ <em>u(x)</em> ≤ 1 + <em>x</em> ²/2,

then taking the limit on each part as <em>x</em> approaches 0 gives

1 ≤ lim [<em>x</em> → 0] <em>u(x)</em> ≤ 1

and so the limit of <em>u(x)</em> as <em>x</em> → 0 is simply 1.

7 0
3 years ago
H. 539.28 - 6.42<br><br> Help pls
My name is Ann [436]

Answer:

532.86

Step-by-step explanation:

just subtract starting with the numbers after the decimal place

6 0
3 years ago
Awarding 90 Points
Amanda [17]

Answer:

  • 1090

Step-by-step explanation:

<h3>Given AP </h3>
  • a₁₂ = 62
  • a₂₀ = 102
<h3>To find</h3>
  • S₂₀
<h3>Solution</h3>
  • a₁₂ = a + 11d = 62
  • a₂₀ = a + 19d = 102

<u>Subtract the first equation from the second one:</u>

  • 8d = 40
  • d = 5

<u>Find a:</u>

  • a + 11*5 = 62
  • a = 62 - 55
  • a = 7

<u>Find the sum of the first 20 terms:</u>

  • S₂₀ = 1/2*20(a + a₂₀) = 10(7 + 102) = 10(109)= 1090

5 0
3 years ago
Can y’all please help meee
ElenaW [278]

Step-by-step explanation:

a. the domain ={-3, 0, 1, 2}

the range = {6, 2, 0, -3}

the relation is a function

b. the domain = {-1, 2, 1}

the range = { -4, 8, 4}

the relation is not a function

6 0
3 years ago
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