(4) total number of valence electrons, because they exist in the same group.
Answer:
ΔT = 20.06 °C
Explanation:
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 1.17 kJ = 1170 J
m = mass = 24.1 g
Cp = Specific Heat Capacity = 2.42 J.g⁻¹.°C⁻¹
ΔT = Change in Temperature = <u>??</u>
Solving eq. 1 for ΔT,
ΔT = Q / m Cp
Putting values,
ΔT = 1170 J / 24.1 g × 2.42 J.g⁻¹.°C⁻¹
ΔT = 20.06 °C
Answer:
2. For any given isotope, the sum of the numbers of protons and neutrons in the nucleus is called the mass number.
3. in fact, electron mass is so small that it is not counted in an atom's mass
Explanation:
AgNO3 + NaCl ---> AgCl(s)
+ NaNO3
find moles of each
mmol = M*V
mmol = 55*1 = 55 mmol of Ag+
mmol = 25 * 1.06 = 26.5 mmol
of Cl-
then limitn greactant is Cl
we can produce up to 26.5
mmol of Agcl
<span>mass = mol*MW = (26.5 * 10^-3)
* 143.32 = 3.7980 g of AgCl</span>
<span> </span>
Answer:
15g so its a hope it helped
Explanation:
