Answer:
12.044 X 10^23 molecules of NaOH
Explanation:
because NaOH is an ionic bond, we should be asking how many <em>formula units </em> are in 2 moles of NaOH, there are 0 molecules since NaOH is measured in formula units.
but for the sake of the problem I'll assume NaOH is measured in molecules
for every mol of something there are 6.022 X 10^23 of something of that something.
so there are 6.022 X 10^23 molecules for every mol of NaOH
that means we have 2 X 6.022 X 10^23 molecules in 2 moles of NaOH = 12.044 X 10^23 molecules of NaOH
The answer is degree of ionization. I'm guessing you have already taken the quiz.
'Heavy' hydrogen (the isotope deuterium) , 2/1H is involved ,
[2= mass number, 1= atomic (proton) number]
2/1H + 2/1H → 3/2He + 1/0n
Answer:
Methane -1,Ethene 2 , Ethane 2,Pentane 5,Propene 3,Hexane 6,Ethyne 2,Propane 3,Octane 8,Heptane 7 Decane 10,Butyne 4,Butane 4,Propyne 3,Butene 4
Answer:
Hey!
0.8730 / 9.650 = 8.42445
Explanation:
8.42445 TO 2 s.f... (best option for rounding)
= 8.4
ANSWER = 8.4 (2 s.f)
HOPE THIS HELPS!!
