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irina [24]
3 years ago
14

10. (2 points) What is the process by which a solute forms a solution in a solvent. A) calisthenics B) bumping C) dissolution D)

neutralization E) delineation
Chemistry
1 answer:
Triss [41]3 years ago
4 0

Answer: (C) Dissolution is the process by which a solute form a solution in a solvent.

Explanation: Dissolution can be described as the process by which a solute dissolves in a solvent to give a solvent.

The solute may be a solid, liquid or gas and solvent is usually a liquid but can also be liquid, gas or supercritical fluid. The most common solvent is water and it is referred to as the universal solvent.

Example are:

1.Stirring of sugar in water.

In this case the solute is the sugar and the solvent is water.

2.Organic substances dissolves readily in solvent like kerosene and benzene and they are known as non-polar solvent while the organic substances are the solute

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Which pair of samples contains the same number of oxygen atoms in each compound?0.20 mol Ba(OH)2 and 0.20 mol H2SO40.20 mol Br2O
Whitepunk [10]

Answer:

0.20 mol Br2O and 0.20 mol HBrO have the same number of oxygen atoms

Explanation:

<em>0.20 mol Ba(OH)2 and 0.20 mol H2SO4</em>

In Ba(OH)2 there are 2 moles of O atoms in every mol of Ba(OH)2.

Number of O atoms in 0.20 moles Ba(OH)2 = 2*0.20 = 0.40 moles O atom

In H2SO4 there are 4 moles of O atoms for every mol of H2SO4.

Number of O atoms in 0.20 moles H2SO4 = 4*0.20 = 0.80 moles O atom

⇒ 0.20 mol Ba(OH)2 and 0.20 mol H2SO4 do <u>not</u> have the same number of oxygen atoms.

<em>0.20 mol Br2O and 0.20 mol HBrO</em>

In Br2O there is 1 mol of O atoms in every mol Br2O

Number of O atoms in 0.20 moles Br2O = 0.20*1 = 0.20 moles O atom

In HBrO there is 1 mol of O atom in every mol HBrO

Number of O atoms in 0.20 moles HBrO = 0.20 *1 = 0.20 moles O atom

⇒ in 0.20 moles Br2O and 0.20 moles HBrO we <u>have the same</u> number of oxygen atoms

0.20 moles of Oygen contains: = 0.20 * 6.022*10^23 = 1.2 *10^23 O atoms

<em>0.10 mol Fe2O3 and 0.50 mol BaO</em>

In Fe2O3 there are 3 moles of O atoms in every mol of Fe2O3

Number of O atoms in 0.10 moles Fe2O3 = 0.10 * 3 = 0.30 moles O atom

In BaO there is 1 mol of O atoms in every mol BaO

Number of O atoms in 0.50 mol BaO = 1*0.50 = 0.50 moles O atom

⇒ 0.10 mol Fe2O3 and 0.50 mol BaO do <u>not</u> have the same number of oxygen atoms.

<em>0.10 mol Na2O and 0.10 mol Na2SO4</em>

In Na2O there is 1 mol of O atoms in every mol of Na2O

Number of O atoms in 0.10 mol Na2O = 1*0.10 = 0.10 moles O atom

In Na2sO4 there are 4 moles of O atoms in every mol of Na2SO4

Number of O atoms in 0.10 mol Na2SO4 = 4*0.10 = 0.40 moles O atom

⇒ 0.10 mol Na2O and 0.10 mol Na2SO4 do <u>not</u> have the same number of oxygen atoms.

4 0
3 years ago
Based on the six given solvents, which of the following answers lists ALL of the solvents that are NOT suitable for liquid-liqui
Zina [86]

Answer:

I don't know the answer sorry

6 0
2 years ago
How much states have in united states
Gemiola [76]

Answer:

there are 50 states in the United States

Explanation:

you look at a map and count after that you count Alaska and Hawaii and you have 50

states

8 0
3 years ago
Read 2 more answers
What would the product look like if ROOR weren't used?
S_A_V [24]

Answer:

The least substituted product (anti-Markovnikov)

Explanation:

The ROOR is used in the addition reaction of HBr to an organic substance (an alkene for example).

In normal conditions (with no ROOR) the adition of the halogen will be performed in the most substituted C (following the rule of Markovnikov that says that the stability increases with the more substituted is the C).

But in presence of ROOR, the reaction takes other mechanism (free radicals), and the product in this case is the one with the Br added in the least substituted C.

4 0
3 years ago
6. 7. A hyperbaric chamber has a volume of 200. L. (a) How many moles of oxygen are needed to fill the chamber at room temperatu
Otrada [13]

Answer:

a) 24.7 mol

b) 790 g

Explanation:

Step 1: Given data

  • Volume of the chamber (V): 200. L
  • Room temperature (T): 23 °C
  • Pressure of the gas (P): 3.00 atm

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 23°C + 273.15 = 296 K

Step 3: Calculate the moles (n) of oxygen

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol

Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen

The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.

m = n × M

m = 24.7 mol × 32.00 g/mol = 790 g

6 0
3 years ago
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