All categories

3 years ago

A saturated hydrocarbon is an organic compound which contains hydrogen and carbon joined _____.

Chemistry

2 answers:

Leya [2.2K]3 years ago

8 0

B) with single bonds..... Hope it helps, Have a nice day :)

Harman [31]3 years ago

5 0

Answer:

The correct answer is option B.

Explanation:

Saturated hydrocarbons are the hydrocarbons in which single bond is between carbon and carbon atoms is present.

The general formula for these hydrocarbons is given as:

$C_nH_{2n+2}$

Unsaturated hydrocarbons are defined as the hydrocarbons in which double or triple covalent C-C bonds are there. They are known as alkenes and alkynes respectively.

The general formula for these hydrocarbons are given as:

$C_nH_{2n}$ (alkenes)
$C_nH_{2n-2}$ (alkynes)

You might be interested in

A 100.0 ml sample of 0.18 m hclo4 is titrated with 0.27 m lioh. determine the ph of the solution before the addition of any lioh

snow_lady [41]

Thank you for posting your question here at brainly. Below is the solution:

<span>moles HClO4 = 0.100 L x 0.18 M = 0.018
moles LiOH = 0.030 L x 0.27 = 0.0081
moles H+ in excess = 0.018 - 0.0081 = 0.0099
total volume = 0.130 L
[H+] = 0.0099/ 0.130= 0.0762 M
pH = 1.12</span>

3 0

3 years ago

Give the half equation to show what happens to oxygen when it is rusting

ycow [4]

Answer:

½O 2 + 2e - + H 2O → 2OH.

Explanation:

Redox reactions - Higher

In terms of electrons:

oxidation is loss of electrons

reduction is gain of electrons

Rusting is a complex process. The example below show why both water and oxygen are needed for rusting to occur. They are interesting examples of oxidation, reduction and the use of half equations:

iron loses electrons and is oxidised to iron(II) ions: Fe → Fe2+ + 2e-

oxygen gains electrons in the presence of water and is reduced: ½O2 + 2e- + H2O → 2OH-

iron(II) ions lose electrons and are oxidised to iron(III) ions by oxygen: 2Fe2+ + ½O2 → 2Fe3+ + O2-

3 0

3 years ago

Hellpppppoppopppppppp

Kipish [7]

Answer:

Explanation:

it's always colder at night and close to night especially near water and that's when wind tends to blow the most

8 0

3 years ago

Read 2 more answers

Label the following as either a chemical or a physical change.

Delicious77 [7]

Physical,physical, chemical, chemical, physical, chemical

7 0

3 years ago

Read 2 more answers

The average lung capacity of a human is 6.0L.

Darya [45]

Answer:

(a) 0.25 mol

(b) 0.11 mol

Explanation:

(a)

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 298 K

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$1.00 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1.00\times 6.0}{0.0821\times 298}=0.25mol$

(b)

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 0.296 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 200 K

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$0.296 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 200K\\\\n=\frac{0.296\times 6.0}{0.0821\times 200}=0.11mol$

(c)

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 30 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 250 K

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$30 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 250K\\\\n=\frac{30\times 6.0}{0.0821\times 250}=8.77mol$

8 0

3 years ago