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Fantom [35]
3 years ago
9

A saturated hydrocarbon is an organic compound which contains hydrogen and carbon joined _____.

Chemistry
2 answers:
Leya [2.2K]3 years ago
8 0
B) with single bonds..... Hope it helps, Have a nice day :)
Harman [31]3 years ago
5 0

Answer:

The correct answer is option B.

Explanation:

Saturated hydrocarbons are the hydrocarbons in which single bond is between carbon and carbon atoms is present.

The general formula for these hydrocarbons is given as:

C_nH_{2n+2}

Unsaturated hydrocarbons are defined as the hydrocarbons in which double or triple covalent C-C bonds are there. They are known as alkenes and alkynes respectively.

The general formula for these hydrocarbons are given as:

  • C_nH_{2n} (alkenes)
  • C_nH_{2n-2} (alkynes)
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Arisa [49]

Answer:

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3 0
2 years ago
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) ⇌ 2NO(g) Kc = 4.3 ×
Anuta_ua [19.1K]

Answer:

Kc=~1.49x10^3^4}

Explanation:

We have the reactions:

A: N_2_(_g_) + O_2_(_g_)  2NO_(_g_)~~~~~~Kc = 4.3x10^-^2^5

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~~~Kc = 6.4x10^9

Our <u>target reaction</u> is:

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)

We have NO_(_g_) as a reactive in the target reaction and  NO_(_g_) is present in A reaction but in the products side. So we have to<u> flip reaction A</u>.

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

Then if we add reactions A and B we can obtain the target reaction, so:

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~Kc=6.4x10^9

For the <u>final Kc value</u>, we have to keep in mind that when we have to <u>add chemical reactions</u> the total Kc value would be the <u>multiplication</u> of the Kc values in the previous reactions.

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)~~~Kc=\frac{6.4x10^9}{4.3x10^-^2^5}

Kc=~1.49x10^+^3^4}

3 0
3 years ago
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