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Andrew [12]
3 years ago
10

How many moles of magnesium, Mg, are there in 4.75 grams of magnesium?

Chemistry
1 answer:
Nina [5.8K]3 years ago
3 0
Molar mass Mg = 24.3 g/mol

1 mole mg ------------ 24.3 g
?? moles mg --------- 4.75 g

4.75 x 1 / 24.3 => 0.195 moles of Mg

hope this helps!
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32 g of sulfur will react with 48 g of oxygen to produce 80 g of sulfur trioxide. If 32 g of sulfur and 100 g of oxygen are plac
Lina20 [59]

Answer:

Since the container is consealed, and O2 will no be completely consumed, the total mass of material in the container will be 80 grams SO3+ 52 grams O2 = 132 grams (option B)

Explanation:

Step 1: Data given

Mass of sulfur = 32.00 grams

Mass of oxygen = 48.00 grams

Molar mass of sulfur = 32.07 g/mol

Molar mass of oxygen = 32 g/mol

Molar mass of SO3 = 80.07 g/mol

Step 2: The balanced equation

2S + 3O2 → 2SO3

Step 3: Calculate moles S

Moles S = Mass S / molar mass S

Moles S = 32.0 grams / 32.07 g/mol

Moles S = 0.998 moles

Step 4: Calculate moles O2

Moles O2 = 100.0 grams / 32.0 g/mol

Moles O2 = 3.125 moles

Step 5: Calculate the limiting reactant

For 2 moles S we need 3 moles O2 to produce 2 moles SO3

S is the limiting reactant. It will completely be consumed (0.998 moles)

O2 is in excess, there will be consumed 3/2 * 0.998 = 1.497 moles

There will remain 3.125- 1.497 = 1.628 moles O2

This is 1.628 moles * 32 g/mol = 52.1 grams

Step 6: Calculate moles SO3

For 2 moles S we need 3 moles O2 to produce 2 moles SO3

For 0.998 moles S there will react 0.998 moles SO3

Step 6: Calculate mass SO3

Mass SO3 = moles SO3 * molar mass SO3

Mass SO3 = 0.998 moles * 80.07 g/mol

Mass SO3 = 79.9 grams ≈ 80 grams

There will be produced 80 grams of SO3

Since the container is consealed, and O2 will no be completely consumed, the total mass of material in the container will be 80 grams SO3+ 52 grams O2 = 132 grams (option B)

4 0
3 years ago
. In a separate experiment, the molar mass of nicotine is found to be somewhere between 150 and 180 g/mol. Calculate the molar m
stealth61 [152]

Answer:

<h2>         162g/mol</h2>

Explanation:

The question is incomplete. The complete question includes the information to find the empirical formula of nicotine:

<em>Nicotine has the formula   </em>C_xH_yN_z<em> . To determine its composition, a sample is burned in excess oxygen, producing the following results:</em>

  • <em>1.0 mol of CO₂</em>
  • <em>0.70 mol of H₂O</em>
  • <em>0.20 mol of NO₂</em>

<em>Assume that all the atoms in nicotine are present as products </em>

<h2>Solution</h2>

To find the empirical formula you need to find the moles of C, H, and N in each of the compound.

  • 1.0 mol of CO₂ has 1.0 mol of C
  • 0.70 mol of H₂O has 1.4 mol of H
  • 0.20 mol of NO₂ has 0.20 mol of N

Thus, the ratio of moles is:

  • C: 1.0
  • H: 1.4
  • N: 0.20

Divide all by the smallest number: 0.20

  • C: 1.0 / 0.20 = 5
  • H: 1.4 / 0.20 = 7
  • N: 0.20 / 0.20 = 1

Hence, the empirical formula is C₅H₇N

Find the mass of 1 mole of units of the empirical formula:

  • C:  5mol  × 12g/mol = 60g
  • H: 7mol × 1g/mol = 7 g
  • N: 1 mol × 14g/mol = 14g

Total mass = 60g + 7g + 14g = 81g

Two moles of units of the empirical formula weighs 2 × 81g = 162g and three units weighs 3 × 81g = 243 g.

Thus, since the molar mass is between 150 and 180 g/mol, the correct molar mass is 162g/mol and the molecular formula is twice the empirical formula: C₁₀H₁₄N₂.

5 0
3 years ago
The properties of an unknown substance can be compared to the properties of a known substance to identify the unknown substance.
Nitella [24]

Answer:  Physical properties are those that can be determined or measured without changing the composition or identity of the substance. These properties include color, odor, taste, density, melting point, boiling point, conductivity, and hardness.

Explaination:

By using Physical properties unknown substance can be identified as it involves determination of a substance with out changing their composition or property include color, odor, taste, density, melting point etc.

What are the difference between physical and chemical property ?

Chemical properties can be observed or measured when a substance undergoes any type of changes chemically while Physical properties can be observed without changing anything.

In chemical property, chemical reaction is conducted to show the property of the substance while in physical property No chemical reaction occur.

Chemical properties related to chemical bonds while Physical properties do not have such a relationship.

Chemical properties include radioactivity, toxicity, flammability, heat of combustion,  etc. while physical properties include Molecular weight, boiling point, melting point, freezing point, volume, mass, length, density shape, solubility, etc.

<em>If this helped you please consider marking this as the Brainliest Answer, if i make it to 10, I can be promoted to an expert. How? - Once you get more than 1 answer of a question. A message is shown above each answer that is "Mark as brainiest". Click on the option to mark it the best answer. Thank you!</em>

5 0
1 year ago
5. If a block of wood has a density of 0.6 g/cm3 and a mass of 120 g, what is its volume? (D= M/V)
AlexFokin [52]

Answer:

200 cm^3

Explanation:

V = M/D

V = 120g / (0.6g/cm^3)

V = 200 cm^3

4 0
3 years ago
ATP is a source of free energy that drives unfavorable reactions. Which of the processes are coupled to the dephosphorylation of
geniusboy [140]

Answer:

b,c and d

Explanation:

The following  processes are coupled to the dephosphorylation of ATP

b. the endergonic reaction forming gluco-6-phosphate

c. Myosin action during muscle contraction

d. de novo anabolism of nucleotide

5 0
3 years ago
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