Answer:
a)
b)
Explanation:
a)
The width of the central bright in this diffraction pattern is given by:
when m is a natural number.
here:
- m is 1 (to find the central bright fringe)
- D is the distance from the slit to the screen
- a is the slit wide
- λ is the wavelength
So we have:
b)
Now, if we do m=2 we can find the distance to the second minima.

Now we need to subtract these distance, to get the width of the first bright fringe :
I hope it heps you!
Answer:
Newton's Second Law of Motion
Explanation:
According to Newton's second law of motion, the change in velocity of a body is directly proportional to the force applied on it. Velocity is a vector quantity. It measures the magnitude of the speed as well as its direction.
F = m a
where, F is the applied force, m is the mass and a is the acceleration.
It can also be expressed as:

where, p = mv ( momentum)
U = mgh, Ek = 1/2*m*v^2
U = Ek (conservation of mechanical energy)
⇒ mgh = 1/2*m*v^2
∵g = 10, v = 20
⇒ 10h = 1/2*400
⇒ h = 20 (m)
Answer:
The Position of the object L = 0.172 m
Explanation:
The detailed explanation of the question is given in the attach document.
We have that the maximum rank of the kangaroo is given by:
R = v0 ^ 2 sin (2θ) / g
where,
v0 = initial velocity
θ = angle of the velocity vector formed from the horizontal
g = gravity
Clearing the speed we have:
v0 ^ 2 = (R * g) / (sin (2θ))
Substituting values
v0 = root (((11) * (9.8)) / (sin (2 (21 * (pi / 180)))))
v0 = 12.69 m / s
answer
its takeoff speed is 12.69 m / s