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Papessa [141]
3 years ago
14

An osprey's call is a distinct whistle at 2200 hz. an osprey calls while diving at you, to drive you away from her nest. you hea

r the call at 2300 hz. part a how fast is the osprey approaching? express your answer to two significant figures and include the appropriate units. v = request answer provide feedback diving
Physics
1 answer:
STatiana [176]3 years ago
6 0
While the osprey is approaching, the frequency of his whistle is shifted according to the formula (Doppler effect)
f' =  \frac{v}{v-v_s} f
where 
f is the original frequency of the whistle (2200 Hz)
f' is the apparent frequency (2300 Hz)
v is the speed of sound in air (340 m/s)
vs is the speed of the source (the osprey) moving towards the observer 

We can re-arrange the formula to find vs, the speed of the osprey relative to the observer:
v_s =  \frac{f'-f}{f'} v= \frac{2300 Hz-2200 Hz}{2300 Hz} (340 m/s)=15 m/s
so, the osprey is approaching at 15 m/s.
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Thomson's experiments accounted for: the mass of the electron the fundamental charge the force on a current-carrying wire the el
gogolik [260]

Thomson experiment he calculated the charge to mass ratio just be passing the fundamental charge through a tube

He calculated the charge to mass ratio just by finding the deflection of charge while it is passing through the constant electric field

so here we will use the deflection as following

let say it passes the field of length "L"

so here we have

t = \frac{L}{v}

now in the same time if it deflect by some distance

\delta y = \frac{1}{2}at^2

\delta y = \frac{1}{2}{eE}{m}t^2

now by solving this equation we can find e/m ratio

so here correct answer will be

the electron's charge-to-mass ratio

7 0
3 years ago
Read 2 more answers
Which is greater, the gravitational force between earth and the moon, or the force between earth and the sun?
Karo-lina-s [1.5K]
Earth and the Sun
GF = 3.647x10^22 N
8 0
4 years ago
A bullet of mass 6.20 10-3 kg, moving at 1320 m/s impacts a tree stump and penetrates 11.00 cm into the wood before coming to re
sladkih [1.3K]

Answer:

  F = -49.1   10³ N

Explanation:

Let's use the kinematics to find the acceleration the acceleration of the bullet that they tell us is constant

   v_{f}² = v₀² + 2 a x

Since the bullet is at rest, the final speed is zero

    x = 11.00 cm (1 m / 100 cm) = 0.110 m

    0 = v₀² + 2 a x

   a = -v₀² / 2 x

   a = -1320²/(2 0.110)

   a = -7.92 10⁶ m / s²

With Newton's second law we find the force

   F = m a

   F = 6.20 10⁻³ (-7.92 10⁶)

   F = -49.1   10³ N

The sign means that it is the force that the tree exerts to stop the   bullet

8 0
3 years ago
One end of a 7-cm-long spring is attached to the ceiling. When a 5.4 kg mass is hung from the other end, the spring is stretched
mash [69]

Answer:

2.63 cm

Explanation:

Hooke's law gives that the force F is equal to cy where c is spring constant and x is extension

Making c the subject of the formula then

c=\frac {F}{y}

Since F is gm but taking the given mass to be F

c=\frac {5.4 kg}{4.3 cm}=1.2558139534883720930232558139534883720930

By substitution now considering F to be 3.3 kg

y=\frac {3.3 kg}{1.2558139534883720930232558139534883720930}=2.6277777777777 cm\approx 2.63 cm

8 0
4 years ago
Septum: Left and right atrium: Pacemaker: Left and right ventricles: Valves:
hammer [34]
Can you define the question further.

This may help with your answer:

Tricuspid valve. This valve is located between the right atrium and the right ventricle.
Pulmonary valve. The pulmonary valve is located between the right ventricle and the pulmonary artery.
Mitral valve. This valve is located between the left atrium and the left ventricle. It has only 2 leaflets.
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