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Kipish [7]
3 years ago
13

Indique onde em quantos metros o rapaz chegará com as seguintes condições: S0 = 0 a) v = 3 m/s e t = 2 s b) v = 2 m/s e t = 3,5

s c) v = 10 m/s e t = 0,5 s d) v = 4 m/s e t = 2,5 s e) v = 1,5 m/s e t = 5 s
é pra hoje por vapor me ajudem
Physics
1 answer:
Naily [24]3 years ago
8 0

Answer:

I will answer in English.

Here we will use the relation

Velocity*time = distance

So:

a) velocity = 3m/s

time = 2s

Distance = 3m/s*2s = 6m

b) velocity = 2m/s

time = 3.5s

Distance = 2m/s*3.5s = 7m

c) velocity = 10m/s

time = 0.5s

Distance = 10m/s*0.5s = 5m

d) velocity = 4m/s

time = 2.5s

Distance = 4m/s*2.5s = 9m

e) velocity = 1.5m/s

time = 5s

Distance = 1.5m/s*5s = 7.5m

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Gnoma [55]

Answer:

20 J

Explanation:

KE = ½ mv²

KE = ½ (10 kg) (2 m/s)²

KE = 20 J

7 0
3 years ago
. A 65 kg climber on top of Mt. Everest (8800 m high). How much Pontential Energy does he have?
Kruka [31]

Answer:

He has 5,609,404 J of potential energy

Explanation:

P.E. = M*G*H

65 * 9.8^2 * 8800

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3 years ago
A square wave has amplitude 0 V for the low voltage and 4 V for the high voltage. Calculate the average voltage by integrating o
Margarita [4]

Answer:

V_{average} = \frac{1}{2}  V_o  ,     V_{average} = 2 V

Explanation:

he average or effective voltage of a wave is the value of the wave in a period

            V_average = ∫ V dt

in this case the given volage is a square wave that can be described by the function

           V (t) = \left \{ {{V=V_o \ \ \  t<  \tau /2} \atop {V=0 \ \  \ \  t> \tau /2 }   } \right.

to substitute in the equation let us separate the into two pairs

             V_average = \int\limits^{1/2}_0 {V_o} \, dt + \int\limits^1_{1/2} {0} \, dt

             V_average = V_o \ \int\limits^{1/2}_0 {} \, dt

             V_{average} = \frac{1}{2}  V_o

we evaluate  V₀ = 4 V

             V_{average} = 4 / 2)

             V_{average} = 2 V

6 0
3 years ago
Determine Force. 589J of work was accomplished over a distance of 1100m, how much force was exerted? Include the correct units.
LiRa [457]

Answer:

Explanation:

Given:

A = 589 J

D = 1 100 m

____________

F - ?

A = F·D

F = A / D = 589 / 1100 ≈ 0.54 N

5 0
1 year ago
What happens to the distance physics help please? The frequency of a wave increases. What happens to the distance between succes
aliya0001 [1]
For any periodic wave 
<span>v = f λ </span>

<span>where </span>
<span>v = velocity </span>
<span>f = frequency </span>
<span>λ = wavelength (distance between 2 successive crests) </span>

<span>This means that </span>
<span>λ = v/f </span>

<span>Assuming that v stays the same while f increases, λ must DECREASE.

I hope this helps

</span>
4 0
3 years ago
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