Answer:
He has 5,609,404 J of potential energy
Explanation:
P.E. = M*G*H
65 * 9.8^2 * 8800
Answer:
V_{average} =
, V_{average} = 2 V
Explanation:
he average or effective voltage of a wave is the value of the wave in a period
V_average = ∫ V dt
in this case the given volage is a square wave that can be described by the function
V (t) = 
to substitute in the equation let us separate the into two pairs
V_average = 
V_average = 
V_{average} = 
we evaluate V₀ = 4 V
V_{average} = 4 / 2)
V_{average} = 2 V
Answer:
Explanation:
Given:
A = 589 J
D = 1 100 m
____________
F - ?
A = F·D
F = A / D = 589 / 1100 ≈ 0.54 N
For any periodic wave
<span>v = f λ </span>
<span>where </span>
<span>v = velocity </span>
<span>f = frequency </span>
<span>λ = wavelength (distance between 2 successive crests) </span>
<span>This means that </span>
<span>λ = v/f </span>
<span>Assuming that v stays the same while f increases, λ must DECREASE.
I hope this helps
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