Kara shines a blue light and a red light onto paper as shown in the figure below. If the paper is

A chemist prepares a solution of magnesium chloride MgCl2 by measuring out 49.mg of MgCl2 into a 100.mL volumetric flask and fil

Flura [38]

Answer: Molarity of $Cl^-$ anions in the chemist's solution is 0.0104 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.049g}{95g/mol}=5.2\times 10^{-4}moles$

$V_s$ = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{5.2\times 10^{-4}moles\times 1000}{100ml}=5.2\times 10^{-3}mole/L$

Therefore, the molarity of solution will be $5.2\times 10^{-3}mole/L$

$MgCl_2\rightarrow Mg^{2+}+2Cl^-$

As 1 mole of $MgCl_2$ gives 2 moles of $Cl^-$

Thus $5.2\times 10^{-3}$ moles of $MgCl_2$ gives = $\frac{2}{1}\times 5.2\times 10^{-3}=0.0104$

Thus the molarity of $Cl^-$ anions in the chemist's solution is 0.0104 M

6 0

3 years ago

How many atoms (mol) is in 10g of sodium, sodium chloride and Iron chloride?

SashulF [63]

Answer:

See explanation

Explanation:

Molar mass of NaCl = 58.5 g

Number of moles contained in 10 g of NaCl = 10 g/58.5 g = 0.17 moles

If 1 mole of NaCl contains 6.02 * 10^23 atoms

0.17 moles of NaCl contains 0.17 * 6.02 * 10^23 atoms = 1.02 * 10^23 atoms

Molar mass of Fe II chloride = 126.751 g/mol

Number of moles = 10 g/126.751 g/mol = 0.0789 moles

Number of atoms = 0.0789 moles * 6.02 * 10^23 atoms = 4.7 * 10^22 atoms

Molar mass of Na = 23 g/mol

Number of moles = 10g/23 g/mol = 0.43 moles

Number of atoms = 0.43 moles * 6.02 * 10^23 atoms = 2.59 * 10^ 23 atoms

8 0

3 years ago

Identify the gas law that applies to the following scenario: A 36.5 liter balloon holding 2.9 moles of carbon dioxide leaks. If

jarptica [38.1K]

Answer:

Avogadro's Law; 15.1L

Explanation:

Boyle's Law- Pressure and volume are inversely related, so an increase in pressure= decrease in volume. We see this in the equation P1V1=P2V2.

Charle's Law- Gas expands/increases in volume when temperature increases, so they are proportional. We see this in the formula $\frac{V1}{T1} = \frac{V2}{T2}$ .

Guy-Lussac's Law- As temperature increases, pressure increases, so they are proportional. We see this in the formula $\frac{P1}{T1} = \frac{P2}{T2}$ .

Avogadro's Law- There are equal amount of volume have an equal amount of moles, so they are proportional. We see this in the formula $\frac{V1}{n1} = \frac{V2}{n2}$ .

Plugging in the values based on Avogadro's Law, we'll have:

$\frac{36.5}{2.9} = \frac{V2}{1.2}$

12.6 = $\frac{V2}{1.2}$

12.6 x 1.2 = V2

15.1L =V2

6 0

3 years ago

What quantity of copper is deposited by the same quantity of electricity that deposited 9g of aluminum

klio [65]

Answer:

Mass of copper deposited = 31.75 g

Explanation:

According to Faraday's second law of electrolysis, when the same quantity of electricity is passed through different electrolytes, the relative number of moles of the elements deposited are inversely proportional to the charges on the ions of the elements.

From this law, it can be seen that the higher the charge, the lower the number of moles of a given element deposited.

Number of moles of aluminium in 9 g of aluminium = mass / molar mass

Molar mass of aluminium = 27 g

Number of moles of aluminium = 9/27 = 1/3 moles

Charge on aluminium ion = +3

3 moles of electrons will discharge 1 mole of aluminium,

1 mole of electrons will discharge 1/3 moles of aluminium

Number of moles of electrons involved = 1 mole of electrons

Charge on copper ion = +2

1 mole of electrons will discharge 1/2 moles of copper.

Mass of 1/2 moles of copper = number of moles × molar mass of copper

Molar mass of copper = 63.5 g

Mass of copper deposited = 1/2 × 63.5 = 31.75 g

3 0

3 years ago

The structure of graphite and diamond come under what structure

Elis [28]

Graphite and diamond come under covalent structure.

6 0

3 years ago

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